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2 years ago

PLEASE HELP ASAPPP!!! tank youuu

Mathematics

2 answers:

frozen [14]2 years ago

6 0

Answer:

Step-by-step explanation:

The person above got it right give brainliest to her/he

erastovalidia [21]2 years ago

5 0

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Tina's aquarium has a capacity of 40 gallons or water. She plans to stock her aquarium with 0.25 inches of fish per quart of cap

Sonbull [250]

Answer:

The number of mollies fishes in the aquarium is 20 .

Step-by-step explanation:

Given as :

The capacity of aquarium = 40 gallons

∵ 1 gallon = 4 quart

∴ 40 gallons = 4 × 40 = 160 quart

Now, According to question

0.25 inches of fish required 1 quart capacity

I.e for 1 quart capacity , 0.25 inches fish

So. for 160 quart capacity , 0.25 × 160 = 40 inches fishes

Now the size of mollies fish = 2 inches

Then , number of mollies fish = $\dfrac{\textrm total size of fishes}{\textrm size of mollies fish}$

I.e Number of mollies fish = $\frac{40}{2}$ = 20

Hence The number of mollies fishes in the aquarium is 20 . Answer

3 0

2 years ago

5 múltiplos de 7 mayores que 140

expeople1 [14]

35 hbgghhhhhhvcgghhghu

6 0

2 years ago

The inches of rainfall in the rainforest is represented by the function f(x) = 3(x-2)+ 4. What is the average rate of change bet

nata0808 [166]

Answer:

The average rate of change of rainfall in the rainforest between 2nd year and 6th year = 3 inches

Step-by-step explanation:

Given function representing inches of rainfall:

$f(x)=3(x-2)+4$

To find the average rate of change between the 2nd year and the 6th year.

Solution:

The average rate of change between interval $[a,b]$ is given as :

$\frac{f(b)-f(a)}{b-a}$

For the given function we need to find the average rate of change between 2nd year and 6th year. $[2,6]$

So, we have:

$f(2)=3(2-2)+4=3(0)+4=4$

$f(6)=3(6-2)+4=3(4)+4=12+4=16$

Thus, average rate of change will be:

$\frac{f(6)-f(2)}{6-2}$

⇒ $\frac{16-4}{6-2}$

⇒ $\frac{12}{4}$

⇒ $3$

Thus, the average rate of change of rainfall in the rainforest between 2nd year and 6th year = 3 inches

8 0

3 years ago

HELLPP. ITS URGENT.50 PTS

ICE Princess25 [194]

Answer:

4x² - 13x + 8 = 0
4x² - 11x + 5 = 0
16x² - 41x + 1 = 0
x² + 5x + 4 = 0
x² - 66x + 64 = 0

Step-by-step explanation:

Given

α and β are roots of 4x²-5x-1=0

Then the sum and product of the roots are:

α+b = -(-5)/4 = 5/4
αβ = -1/4

(i) Roots are α + 1 and β + 1, then we have:

(x - (α + 1))(x - (β + 1)) = 0
(x - α - 1)(x - β - 1) = 0
x² - (α+β+2)x + α+β+ αβ + 1 = 0
x² - (5/4+2)x +5/4 - 1/4 + 1 = 0
x² - 13/4x + 2= 0
4x² - 13x + 8 = 0

(ii) Roots are 2 - α and 2 - β, then we have:

(x + α - 2)(x + β - 2) = 0
x² + (a + β - 4)x - 2(α + β) + αβ + 4 = 0
x² + (5/4 - 4)x - 2(5/4) - 1/4 + 4 = 0
x² - 11/4x - 10/4 - 1/4 + 16/4 = 0
x² - 11/4x + 5/4x = 0
4x² - 11x + 5 = 0

(iii) Roots are α² and β², then:

(x - α²)(x-β²) = 0
x² -(α²+β²)x + (αβ)² = 0
x² - ((α+β)² - 2αβ)x + (-1/4)² = 0
x² - ((5/4)² -2(-1/4))x + 1/16 = 0
x² - ( 25/16 + 1/2)x + 1/16 = 0
x² - 33/16x + 1/16 = 0
16x² - 33x + 1 = 0

(iv) Roots are 1/α and 1/β, then:

(x - 1/α)(x - 1/β) = 0
x² - (1/α+1/β)x + 1/αβ = 0
x² - ((α+β)/αβ)x + 1/αβ = 0
x² - (5/4)/(-1/4)x - 1/(-1/4) = 0
x² + 5x + 4 = 0

(v) Roots are 2/α² and 2/β², then:

(x - 2/α²)(x - 2/β²) = 0
x² - (2/α² + 2/β²)x + 4/(αβ)² = 0
x² - 2((α+β)² - 2αβ)/(αβ)²)x + 4/(αβ)² = 0
x² - 2((5/4)² - 2(-1/4))/(-1/4)²x + 4/(-1/4)² = 0
x² - 2(25/16 + 8/16)/(1/16)x + 4(16) = 0
x² - 2(33)x + 64 = 0
x² - 66x + 64 = 0

3 0

2 years ago

Read 2 more answers

The value -2 is a lower bound for the zeros of the function shown below.

Juliette [100K]

Answer:

a) true

Step-by-step explanation:

The bottom-line numbers from synthetic division alternate signs, indicating that -2 is a lower bound. The given statement is true.

If the signs were all positive, it would indicate the proposed zero is an upper bound.

A graph shows all real zeros are greater than -2.

4 0

3 years ago