<span>GUI is a graphical user interface. It is a graphical window that provides interaction with the user.
</span>The button is a pushbutton, which can be pressed to trigger an action.<span>
A graphic control component or a control element is a component that provides a button control in a GUI application. It is also called a control element because it </span><span>is an element of interaction between the user controlling the application.</span>
def is_list_even(my_list):
for i in my_list:
if(i%2 != 0):
return False
return True
def is_list_odd(my_list):
for i in my_list:
if(i%2 == 0):
return False
return True
def main():
n = int(input())
lst = []
for i in range(n):
lst.append(int(input()))
if(is_list_even(lst)):
print('all even')
elif(is_list_odd(lst)):
print('all odd')
else:
print('not even or odd')
if __name__ == '__main__':
main()
Answer:
URI is the uniform resource identifier and it is basically a sequence of the character which identify the physical and logical resources. The uniform resource identifier basically contain the predefined set of rules and syntax and also maintain the extensibility hierarchical schema.
There are basically two types of URI that are:
1) Uniform Resource Name (URN)
2) Uniform Resource Locator (URL)
For example: HTTP protocol , file transfer protocol (FTP).
Answer:
bool identicaltrees(Node* root1,Node* root2)//function of type boolean true if idenctical false if not.
{
if(root1==NULL&&root2==NULL)//both trees are null means identical.
return true;
if(roo1 && root2)
{
if(root1->data==root2->data)//condition for recursive call..
{
return (identicaltrees(root1->left,root2->right)&&identicaltrees(root1->right&&root2->right);
}
}
else
return false;
}
Explanation:
In this function it of type boolean returns true if both the trees are identical return false if not.First we are checking root node of both the trees if both are null then they are identical returning true.
If both root nodes are not null then checking their data.If data is same then recursively traversing on both trees and checking both trees.
else returning false.
I am guessing "A" because you can store code anywhere and file structure does not prevent viruses.
hope this helped
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