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3 years ago

For a projectile launched at an angle, are the forces in the vertical direction balanced or unbalanced?

Physics

2 answers:

marissa [1.9K]3 years ago

8 0

Unbalanced because of the different forces pulling and pushing in certain directions

mart [117]3 years ago

7 0

Unbalanced as long as it is moving up or down. Immediately after being fired the vertical force from the launch will be greater than the force of gravity. for an instant at the the beginning of the projectiles decent the force will actually be balanced and there will be no vertical movement. After that the force of gravity is greater.

tl;dr they are unbalanced

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Two argon atoms form the molecule Ar2 as a result of a van der Waals interaction with U0 = 1.68×10-21 J and R0= 3.82×10 the freq

mel-nik [20]

Answer:

$\mathbf{f_o =1.87 \times 10^{11} \ Hz}$

Explanation:

From the given information:

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m = mass of each atom = 1.66 × 10⁻²⁶ kg

$f_o = \dfrac{1}{2 \pi}\sqrt{\dfrac{2.3 \times 10^{-2} N/m}{1.66 \times 10^{-26} \ kg}}$

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6 0

3 years ago

A 5.75 mm high firefly sits on the axis of, and 11.3 cm in front of, the thin lens A, whose focal length is 5.77 cm . Behind len

weeeeeb [17]

Answer

given,

focal length of lens A = 5.77 cm

focal length of lens B= 27.9 cm

flies distance from mirror = 11.3 m

now,

Using lens formula

$\dfrac{1}{f} = \dfrac{1}{p} + \dfrac{1}{q}$

$\dfrac{1}{5.77} = \dfrac{1}{11.3} + \dfrac{1}{q}$

q =11.79 cm

image of lens A is object of lens B

distance of lens = 59.9 - 11.79 = 48.11

now, Again applying lens formula

$\dfrac{1}{f} = \dfrac{1}{p} + \dfrac{1}{q'}$

$\dfrac{1}{27.9} = \dfrac{1}{48.11} + \dfrac{1}{q'}$

q' =66.41 cm

hence, the image distance from the second lens is equal to q' =66.41 cm

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3 years ago

Pierre cycles at 4 miles per hour and travels a distance of 13 miles. How long

amm1812

Answer:

His journey took him 3 hours 15 minutes.

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4 0

4 years ago

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