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LekaFEV [45]
3 years ago
14

Bernie is driving down a highway at 28m/s. When bernie approaches a stop light, he presses on his brakes to bring his car to a s

top at a constant rate of acceleration. how come bernie decrease the impulse he experiences as his car comes to a stop?
A. he could decelerate over a shorter distance
B. he could decelerate over a shorter period of time
C. he could accelerate to 30m/s before braking
D. he could apply his brakes over a longer period of time
Physics
1 answer:
coldgirl [10]3 years ago
4 0

Answer:

Explanation:B

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8 0
3 years ago
a 5kg block on a rough horizontal surface is attached to a light spring (force constant=1.6kN/m). the block passes through its e
natima [27]

Answer:

2.12 J

Explanation:

Initial kinetic energy = final elastic energy + work by friction

KE = EE + W

KE = ½ kx² + W

5 J = ½ (1600 N/m) (0.06 m)² + W

W = 2.12 J

5 0
3 years ago
What is carnot engine.express the relation for its efficiency?​
patriot [66]

Answer:

Explanation:

The Carnot cycle is a special case of a thermodynamic cycle that produces an ideal gas and consists of two isothermal  processes and two adiabatic processes. This cycle is a theoretical solution given by Sadi Karnot to refine heat engines for their efficient use.

The formula for the coefficient of efficiency is:

η = (Q₁ - Q₂) / Q₁ = (T₁ - T₂) / T₁

Where Q₁ is is the amount of heat of the heater supplied to the working body and Q₂ is the amount of heat that the working body transfers to the refrigerator according to this T₁ is the temperature of the heater T₂ is the temperature of the refrigerator.

This formula provides a theoretical limit for the maximum value of the coefficient of efficiency of heat engines.

God is with you!!!

6 0
4 years ago
Read 2 more answers
Ice-skater slides toward a sled sitting on the ice and hits it. The skater exerts a 12.6 N force on the sled at an angle of 15.3
RideAnS [48]

Answer:

Expression of work done is

W = Fd cos\theta

Work done to move the sled is given as 187.2 J

Explanation:

As we know that the formula of work done is given as

W = Fd cos\theta

here we know that

F = 12.6 N

d = 15.4 m

\theta = 15.3 degree

so we will have

W = 12.6 \times 15.4 cos15.3

W = 187.2 J

5 0
3 years ago
At a certain moment, a car travelling at 40mph begins braking for a railroad crossing. Assume thatthe acceleration is constant (
egoroff_w [7]

Answer:

Part a)

v_f = 17.88 - (0.15) t

Part b)

d = 1072.8 m

Explanation:

As we know that initial speed of the car is

v = 40 mph

v = 40 \times (\frac{1609}{3600})

v = 17.88 m/s

now we have

v_f = v_i + at

0 = 17.88 + a(120)

a = -0.15 m/s^2

Part a)

As we know that acceleration is constant here

so we have

v_f = v_i + at

v_f = 17.88 - (0.15) t

Part b)

distance moved by the car is given as

d = \frac{v_F + v_i}{2} t

now we have

d = \frac{0 + 17.88}{2}(120)

d = 1072.8 m

3 0
3 years ago
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