The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
</u>
Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
30°, 70°, and 80°.
It is an acute-angled triangle.
Explanation:
The ratio of the measures of ∠s in Δ is 3:7:8.
So, let us suppose that the measures are, 3k, 7k, 8k.
Evidently, their sum is
180°.
3k+7k+8k=180
18k=180
k= 10
Hence, the measures are,
30°, 70°, and 80°.
As all the angles are acute, so is the triangle.
Answer:
If
y
varies inversely as
x
then
XXX
x
⋅
y
=
c
for some constant
c
We are told when
x
=
2
then
y
=
15
So
XXX
2
⋅
15
=
c
XXX
⇒
c
=
30
and
XXX
x
⋅
y
=
30
Therefore when
y
=
3
XXX
x
⋅
3
=
30
XXX
→
x
=
10
Step-by-step explanation:
