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Romashka-Z-Leto [24]
3 years ago
7

How to simplify 6 +8b^2 +3b -6 - 10b^2

Mathematics
1 answer:
kozerog [31]3 years ago
5 0

Answer:

-2b^2+3b

Step-by-step explanation:

You just have to add like terms, which is the single numbers, the numbers with just the variables, and the numbers with variables that are squared.

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What is the lateral surface area of the prism in square inches?
Fiesta28 [93]

Answer:

  875 square inches

Step-by-step explanation:

The lateral area of a triangular prism is the sum of the areas of the three rectangular faces:

  13×25 +15×25 +7×25 = (13 +15 +7)×25 = 35×25

  = 875 . . . square inches

_____

The area of a rectangle is the product of its length and width. As we have seen here, the lateral area is the product of the height of the prism and the perimeter of its base.

7 0
3 years ago
Choose the three equivalent expressions: (Select all that apply 6( 4x + 5y) 20x + 30y 2(10x + 3y) 10(2x) + 10( 3y) 10(2x + 3y)​
mart [117]

Answer

Option 2, 4 and 5 :)

Step-by-step explanation:

Option 2 is already simplified to 20x + 30y

Option 4,

10*2x=20x and 10*3y= 30y so option 4 also simplifies to 20x + 30y

Next Option 5, 10*2x= 20x and 10*3y=30y. So it's also 20x + 30y

4 0
3 years ago
An isosceles triangle has exactly two sides that are equal in length​ (congruent). If the base​ (the third​ side) measures 46 in
alexira [117]

Answer:

36.5 Inches

Step-by-step explanation:

The perimeter of the triangle is the sum of all three(3) sides.

let the length of one congruent side be 'a', Therefore;

a + a  + 46 = 119

2a = 119 - 46

a = 73/2

a = 36.5 inches.

7 0
3 years ago
The measure of 13 of the 14 angles of a 14-gon add up to 2012 degrees. What must the fourteenth angle measure be
skelet666 [1.2K]
The total of the internal angles in a tetradecagon is 2160.

2160 - 2012 = 148

The remaining angle must be 148 degrees.
5 0
3 years ago
Manufacture wants to enlarger it's floor area 1.5 times that of the current facility. The current facility is 260 ft by 140 ft.
Lady bird [3.3K]

Answer:

New dimensions of the floor is approximately 301.25 ft by 181.25 ft

Step-by-step explanation:

The question is incomplete. The complete question should be:

Manufacture wants to enlarger it's floor area 1.5 times that of the current facility. The current facility is 260 ft by 140 ft. The manufacture wants to increase each dimension the same amount. Write the dimensions of the new floor.

Given:

Length of floor = 260 ft

Width of floor = 140 ft

The floor area is increased 1.5 times.

To find the new dimensions of the floor.

Solution:

Original area of the floor = length\times width= 260\times 140=36400\ ft^2

New area = 1.5\times Original\ Area = 1.5\times 36,400=54,600\ ft^2

Let the length and width be increased by x ft.

Thus, new length = (260+x)\ ft

New width = (140+x)\ ft

Area of the new floor can be given as:

⇒ new\ length\times new\ width

⇒ (260+x)(140+x)

Multiplying using distribution.

⇒ x^2+260x+140x+36400

⇒ x^2+400x+36400

Thus we can equate this with new area to get the equation to find x

x^2+400x+36400=54600

subtracting both sides by 54600.

x^2+400x+36400-54600=54600-54600

x^2+400x+18200=0

Using quadratic formula:

For a quadratic equation ax^2+bx+c=0

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

For the equation x^2+400x-18200=0

x=\frac{-400\pm\sqrt{(400)^2-4(1)(-18200)}}{2(1)}

x=\frac{-400\pm\sqrt{232800)}}{2}

x=\frac{-400\pm482.49}{2}

x=\frac{-400+482.49}{2} \ and\ x= \frac{-400-482.49}{2}

∴ x\approx 41.25 \ and\ x\approx-441.25

Since length is being increased, so we take x\approx41.25

New dimensions are:

New length \approx 260\ ft + 41.25\ ft =301.25\ ft

New width \approx 140\ ft + 41.25\ ft =181.25\ ft

3 0
3 years ago
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