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Pepsi [2]
3 years ago
7

PLEASE HELP ASAP

Mathematics
1 answer:
boyakko [2]3 years ago
8 0

Answer:

warwar

Step-by-step explanation:

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Solve 4.05p+14.40= 4.50(p+3)
Lubov Fominskaja [6]
We can solve this problem by using PEMDAS 

PEMDAS stands for 
Parenthesis 
Exponents
Multiply
Add
Subtract

So start with (P+3) () is a parenthesis 
5 0
2 years ago
Read 2 more answers
What is the sum of 7/9 plus 3/5
Ivan

Answer:

\frac{62}{45}

Step-by-step explanation:

8 0
2 years ago
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Please help if you think you hot beautiful kind funny cool please help me please
Juli2301 [7.4K]

Answer/Step-by-step explanation:

The equation of the line that passes through the two points would be correct if each point, when substituted into the equation, satisfy the equation.

This is what I mean:

Given the equation of the line, y = 2x - 5, and the two points (-2, -9) and (3, 1):

For the first point, substitute x = -2, and y = -9 into y = 2x - 5.

Thus:

-9 = 2(-2) - 5

-9 = -4 - 5

-9 = -9 (this is true). It means the line runs through the point (-2, -9)

For the second point, substitute x = 3, and y = 1 into y = 2x - 5

This:

1 = 2(3) - 5

1 = 6 - 5

1 = 1 (this is true). This also means the point, (3, 1) is also a point that the equation runs across.

7 0
2 years ago
Help quick ❗️❗️ Which sequence of transformations will change did your PQRS to figure P’Q’R’S’?
babymother [125]

Answer:

Counterclockwise rotation about the origin by 90° followed by reflection over the Y-axis ⇒ answer (D)

Step-by-step explanation:

* Lets revise the reflection and the rotation of a point

- If point (x , y) reflected across the x-axis

∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

∴ Its image is (-x , y)

- If point (x , y) rotated about the origin by angle 90° counter clockwise

∴ Its image is (-y , x)

- If point (x , y) rotated about the origin by angle 90° clockwise

∴ Its image is (y , -x)

- If point (x , y) rotated about the origin by angle 180°

∴ Its image is (-x , -y)

* There is no difference between rotating 180° clockwise or  

anti-clockwise around the origin

- In our problem

# The vertices of the original figure are:

  P(1 , -3) , Q (3 , -2) , R (3 ,-3) , S (2 , -4)

# The vertices of the image are:

  P' (-3 , 1) , Q' (-2 , 3) , R' (-3 , 3) , S' (-4 , 2)

∵ x and y are switched

∴ The figure is rotated about origin by 90°

∵ The signs of the x-coordinates and the y-coordinates

   didn't change

∴ The rotation is followed by reflection, to know about which

   axis we must to find the images after the rotation

∵ P (1 , -3) ⇒ after rotation 90° counter clockwise is (3 , 1)

∵ Q (3 , -2) ⇒ after rotation 90° counter clockwise is (2 , 3)

∵ R (3 , -3) ⇒ after rotation 90° counter clockwise is (3 , 3)

∵ S (2 , -4) ⇒ after rotation 90° counter clockwise is (4 , 2)

* The images are P' (-3 , 1) , Q' (-2 , 3) , R' (-3 , 3) , S' (-4 , 2)

- The sign of x-coordinates of all of them changed

∴ The rotation followed by reflection over the y-axis

* The answer is ⇒ Counterclockwise rotation about the origin

  by 90° followed by reflection over the Y-axis

7 0
3 years ago
Look at rectangle f, g, h, and j on the grid below. which rectangle has an area of 64 sqare units?
hichkok12 [17]
F= 9 x 7 = 63
G= 19 x 4 = 76
H= 12 x 4 = 48
J = 32 x 2 = 64
J is the answer
8 0
3 years ago
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