1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pepsi [2]
3 years ago
7

PLEASE HELP ASAP

Mathematics
1 answer:
boyakko [2]3 years ago
8 0

Answer:

warwar

Step-by-step explanation:

You might be interested in
Marty collects colorful paper clips. Each week he is sure to add exactly five new paper clips to his collection. Make a table re
ruslelena [56]

Answer:

all of them

Step-by-step explanation:

7 0
2 years ago
In the United States nearly 8 x 10^9 text messages are sent everymonth About how many text messages is this! Find the primefacto
iris [78.8K]
8\times10^9=2^{12}\times5^9

1) Since in the USA 8 x 10 ^9 messages are sent every month, that means that approximately 8 billion messages are sent.

2) We can Prime factorize it:

Note that on the right side we've picked only prime numbers. In this case, 2 and 5.

So we can rewrite 8 x 10^9 as prime factors.

8\times10^9=2^{12}\times5^9

3) Hence, the answer is:

8\times10^9=2^{12}\times5^9

7 0
1 year ago
Which of the tables represents a function? (5 points)
AlladinOne [14]

Answer:

It's table D

Step-by-step explanation:

I just took the test.

3 0
2 years ago
How would you solve
harkovskaia [24]

4r^-3 * 2r^2 =

4*(2r^(-3+2))

= 4*2r^-1

= 4*2(1/r)

= 4*(2/r)

=8/r

4 0
3 years ago
85.87 J or heat energy is added to a 34.8 g mass of substance the temperature rises from 21.76°C
Andru [333]

Answer:

The required specific heat is 196.94 joule per kg per °C  

Step-by-step explanation:

Given as :

The heat generated = Q = 85.87 J

Mass of substance  (m)= 34.8 gram = 0.0348 kg

Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C

Let the specific heat = S

Now we know that

Heat = Mass × specific heat × change in temperature

Or, Q = msΔt

Or, 85.87 = (0.0348 kg ) × S × 12.53°C

Or , 85.87 = 0.4360 × S

Or, S = \frac{85.87}{0.4360}

∴ S = 196.94 joule per kg per °C

Hence the required specific heat is 196.94 joule per kg per °C   Answer

7 0
2 years ago
Other questions:
  • The coordinates of a quadrilateral are (5, 8), (7, 10), (9, 12), and (11, 14). After a transformation, the sign of the x-coordin
    14·1 answer
  • Help me on this math question please
    7·2 answers
  • What is the third quartile of this data set ? 14,18,20,21,25,32,40,44,48
    15·1 answer
  • PLEASE HELP!!!
    15·1 answer
  • Solve the equation for x. Plz help
    5·1 answer
  • from 1970 to 2010 a towns population grew to 120,1500 the population grew at a rate of about 0.5% each year. What was the town's
    9·1 answer
  • the Elephants at the zoo eat 2 3/4 buckets of bananas each day. The zookeeper bought 5 1/2 buckets of bananas. For how many days
    11·1 answer
  • You want to be able to withdraw the specified amount periodically from a payout annuity with the given terms. Find how much the
    6·2 answers
  • Find the mean:<br> {8.5, 7.5, 7.5, 7.5<br> 4, 6, 10,7.5, 6, 7.5}
    14·1 answer
  • Write 12x + 4y= –36 in slope-intercept form. y= x− .
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!