14. 43=5+2n
15.(178-n)*18=678
16.26n-38n=24
17.2n+44=132
It's not hard to find one of those, since there are
an infinite number of them. Here are a few:
18.55000001
18.56
18.57
18.58
18.59
18.591
18.59100001
18.59100002
18.59100003
18.59100004
18.59100005
18.5910006
18.591007
18.59108
18.5919
18.59191
18.59192
18.59193
.
.
etc.
Answer:
Step-by-step explanation:
Let the number of cockles be c and that of winkles be w.
From the first relation,
w = 2c ..........(I)
From the second relation, 6 winkles are accidentally split.
This in equation form means the following:
c/w- 6 = 3/5
By cross multiplication,
5c = 3(w - 6)...........(ii)
We know w = 2c , let’s substitute this into the second equation.
5c = 3(2c - 6)
5c = 6c - 18
Collecting like times, c = 18
And w = 2c = 2(18) = 36
Hence, there were initially 18 cockles and 36 winkles
Answer:
Step-by-step explanation:
㏒ 3+㏒(x+2)=1
㏒3(x+2)=1
3(x+2)=10^1
3x+6=10
3x=10-6=4
x=4/3
so A
3.
![log_{2}x+log_{2}(x+2)=3\\or~log_{2}[x(x+2)]=3\\x(x+2)=2^3\\x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x+4)(x-2)=0\\x=2,-4\\x=-4 ~is~an~extraneous~solution.\\B](https://tex.z-dn.net/?f=log_%7B2%7Dx%2Blog_%7B2%7D%28x%2B2%29%3D3%5C%5Cor~log_%7B2%7D%5Bx%28x%2B2%29%5D%3D3%5C%5Cx%28x%2B2%29%3D2%5E3%5C%5Cx%5E2%2B2x-8%3D0%5C%5Cx%5E2%2B4x-2x-8%3D0%5C%5Cx%28x%2B4%29-2%28x%2B4%29%3D0%5C%5C%28x%2B4%29%28x-2%29%3D0%5C%5Cx%3D2%2C-4%5C%5Cx%3D-4%20~is~an~extraneous~solution.%5C%5CB)
