9945/ 39= 255
If you were to try to divide 99 by thirty five it would not be a whole. You would be able to multiply 39 by 2 to get 78. 99 subtracted by 78 = 21 you would then carry down the 4. to equal 214 you would then figure out 39 multiplied by 5 is the highest number to figure a 195 you would have 19 left over. Carry down your 5 and would have 195. You would have 195 again and then multiply 39 by 5 and it would equal out to 195. Your answer would then be 255.

6 0

3 years ago

Simplify the sqaure root of 39.

Degger [83]

$\sqrt{39}=\sqrt{3\cdot13}\\\\\sqrt{39}=\sqrt{39}-can\ not\ simplify\\\\\sqrt{39}\approx6.245$

7 0

3 years ago

Tickets to a local circus cost $5 for students and $8 for adults. A group of 9 people spent a total of $60. How many adults were

S_A_V [24]

Answer:

Step-by-step explanation:

You need to set up and solve a system of linear equations here.

Let s and a represent the number of students and adults respectively.

Then s + a = 9, and s = 9 - a.

Total ticket cost for the adults was ($8/adult)(a)

and for the students ($5/student)(s).

Total cost of the tickets was then ($8/adult)(a) + ($5/student)(s) = $60.

Then our system of linear equations is:

8a + 5s = 60

a + s = 9, or s = 9 - a. Substituting 9 - a for s, we get:

8a + 5(9 - a) = 60.

Then 8a + 45 - 5a = 60, or 3a = 15.

Solving for a, we get a = 5.

Solving for s using s = 9 - a, we get s = 9 - 5, or s = 4.

There were 5 adults in the group (and 4 students).

3 0

3 years ago