First, subtract 5 from both sides, leaving you with 5
- 30x - 5 = 0
If you use the quadratic formula (a=5), (b=-30), (c=-5)
x=-b +/- √b²-4ac / 2a
x= -(30) +/- √(30)² - 4(5) * (-5) / 2(5)
x= 30 +/- √1000 / 10
x = 3 +/- √10
Answer:
Therefore the required result is 9x-2y =0.
Step-by-step explanation:
Given equation are
x-3y =6.....(1)
-8x-y=6 .....(2)
Subtracting equation (2) from (1)
x - 3y = 6
-8x - y= 6
+ + - [ The sign of equation (2) will be change in case of
_________ subtraction and in case of plus the signs remains same ]
(x+8x)-3y+y=6-6 [ adding the like terms]
⇒9x-2y =0
Therefore the required result is 9x-2y =0.
<span>Lateral Area = (<span>π<span> • r •<span> slant height)
If radius = 2 and
slant height = 3 then
</span></span></span></span>
<span>Lateral Area = (<span>π<span> * 2 * 3)
The lateral area = </span></span></span><span><span><span>18.8495559215
</span>
</span>
</span>
<span>
</span>
The answer is g(x) = x².
Solution:
The graph of h(x) = x²+9 translated vertically downward by 9 units means that each point (x, h(x)) is shifted onto the point (x, h(x) - 9), that is,
(x, h(x)) → (x, h(x) - 9)
The translated graph that represents the function is defined by the expression for g(x):
g(x) = h(x) - 9 = x² + 9 - 9 = x²
h(x) = x²+9 → g(x) = x² shows that the graph of the equation g(x) = x² moves the graph of h(x) = x²+9 down nine units.
