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____ [38]
4 years ago
13

Solve the equation for x by graphing.

Mathematics
1 answer:
juin [17]4 years ago
8 0
D is your answer!!!!
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A jar contains only​ pennies, nickels,​ dimes, and quarters. There are 23 ​pennies, 22 ​dimes, and 20 quarters. The rest of the
goldfiish [28.3K]

<em>Answer:</em>

<em>1. 65 coins</em>

<em>2. 79 - (23 + 22 + 20) = n</em>

<em>Step-by-step explanation:</em>

<em>You can use the expression 23 + 22 + 20 to get the amount of coins that are not nickles. And for two? Try it yourself.</em>

<em>Hope this helps. Have a nice day.</em>

8 0
3 years ago
I need help pls someone
Solnce55 [7]

In this question they've given us the formula and they just want us to plug in the numbers and get the value.


P is the original value, P=$600


r is the depreciation rate, r=10%=0.1


t is the time in years, t=2


A = P(1-r)^t = 600(1 - 0.1)^2 = 600 \cdot .9^2 = 486


Answer: $486






7 0
3 years ago
PLS ANSWER QUICK! Thanks!
ziro4ka [17]

Answer:

The correct answer would be a=\sqrt{c^2-b^2}

Step-by-step explanation:

given a^2+b^2=c^2 we want to solve for a

How?

We can do this by using basic algebra ( isolating the variable (a ))

Step 1 subtract b^2 from each side

a^2+b^2-b^2=a^2\\c^2-b^2=c^2-b^2

now we have a^2=c^2-b^2

step 2 take the square root of each side

\sqrt{a^2} =a\\\sqrt{c^2-b^2} =\sqrt{c^2-b^2}

we're left with a=\sqrt{c^2-b^2}

Hence your answer is A

5 0
3 years ago
The temperature falls from 0 degrees to Negative 12 and one-fourth degrees in 3 and one-half hours. Which expression finds the c
ANEK [815]

Answer:

The expression used to find the change in temperature per hour is Algebraic expression

Thus per hour; the temperature falls at the rate of - 3\dfrac{1}{2}^0

Step-by-step explanation:

A temperature falls from 0 to  - 12\dfrac{1}{4}     in     3\dfrac{1}{2} \ hours

Which expression finds the change in temperature per hour.

From the above given information;

The initial temperature is 0

The final temperature is  - 12\dfrac{1}{4}  

The change in temperature is \Delta T = T_2  -  T_1

\Delta  T = -12\dfrac{1}{4} -0

\Delta T = -12.25

Thus;

-12.25 ° = 3.5 hours

To find the change in x°   per hour; we have;

x°            = 1 hour

The expression used to find the change in temperature per hour is Algebraic expression

From above if we cross multiply ; we have;

(- 12.25° × 1 hour) = (x° × 3.5 hour)

Divide both sides by 3.5 hours; we have:

\dfrac{-12.25^0*1 }{3.5}=\dfrac{ x^0 *3.5}{3.5}

x° =  - 3.5

x° = - 3\dfrac{1}{2}

Thus per hour; the temperature falls at the rate of - 3\dfrac{1}{2}^0

8 0
3 years ago
Help Plez 20 Points Due Today
Jobisdone [24]

Answer:6.25

Step-by-step explanation :  ratio of areas = one half :two point five in a half        

=1.0:6.25

8 0
3 years ago
Read 2 more answers
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