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3 years ago

3. A bicycle wheel has a diameter of 559 mm and has 32 equally spaced spokes. What is the approximate arc

Mathematics

1 answer:

Ronch [10]3 years ago

3 0

Answer:

Arc length = 54.85mm

Step-by-step explanation:

360/32 = 11.25

11.25 * 559 = 6288.75

6288.75 * 3.14 = 19746.675

19746.675/ 360 = 54.851875

Rounded to the nearest hundredth

Arc length = 54.85mm

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Log3 a/3 = ??????????????????????????

Naddik [55]

We have that
Log3 a/3
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we know that
The change of base rule can be used if a and b are greater than 0 and not equal to 1, and x is greater than 0.
so
loga(x)=logb(x)/logb(a)
Substitute in values for the variables in the change of base formula

in this problem
b=10
a=3
x=a/3

log3(a/3)=[log (a/3)]/[log (3)]

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[log (a/3)]/[log (3)]

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3 years ago

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How do you write the sum of one-sixth of n and one-fifth of g

kati45 [8]

Answer: $\frac{n}{6}+\frac{g}{5}$

Step-by-step explanation:

One-sixth of n is n/6.

One-fifth of g is g/5.

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2 years ago

HELPPPP JUST 2 QUESTIONS BASED ON PYTHAGOREAN THEOREM AND IM CONFUSED HELPPPP

Anna007 [38]

9514 1404 393

Answer:

3. no; does not have the correct ratio to other sides

4. (1; right), (2; obtuse), (3; right)

Step-by-step explanation:

3. There are a couple of ways you can go at this.

a) the ratio of sides of a 30°-60°-90° right triangle (half an equilateral triangle) is 1 : √3 : 2. Here, the ratio of sides is ...

(√30/2) : √15 : √30 = 1 : √2 : 2 . . . . MQ is not the height

b) the height is perpendicular to the base, so if MQ were the height, the sides of the triangle would satisfy the Pythagorean theorem:

LQ² +MQ² = LM²

(√30/2)² +(√15)² = (√30)²

30/4 +15 = 30

22.5 = 30 . . . . NOT TRUE

The length MQ cannot be the height of ∆LMN. (It is too short.)

4. To see if these lengths form a right triangle, you can test them in the Pythagorean theorem relation. In the attached we have reformulated the equation so it gives a value of 0 if the triangle is a right triangle:

c² = a² +b² . . . . . Pythagorean theorem

c² -a² -b² = 0 . . . . rewritten

If the value of c² -a² -b² is not zero, then the side lengths do not form a right triangle. The attached shows this math performed by a graphing calculator. The results are ...

right triangle
not a right triangle — long side is too long, so the triangle is obtuse
right triangle

_____

Additional comment

The attached table demonstrates an artifact of computer arithmetic. Not all numbers can be represented exactly in a computer, so a difference that is expected to be zero using exact arithmetic may be slightly different from zero when computed by a computer or calculator. Here, we see a difference of about 6×10^-14 when zero is expected. On most calculators (with 10, or 12 displayed digits), this would be displayed as 0.

The same calculation done "by hand" gives ...

(√425)² -5² -20² = 425 -25 -400 = 0 . . . Triangle 1 is a right triangle