Couple things to note:
- Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
- Slope can be calculated using any two points on a line and the formula y₁ - y₂ / x₁ - x₂.
For the first problem, we know the slope of Function A is 6 (refer to slope-intercept form above). To compare the slopes of Function A and Function B, first find the slope of Function B.
Use y₁ - y₂ / x₁ - x₂. Two points on the line are (0, 1) and (-1, -2). Plug these into the formula accordingly and solve for slope.
y₁ - y₂ / x₁ - x₂
1 - (-2) / 0 - (-1)
1 + 2 / 0 + 1
3 / 1
3
The slope of Function B is 3. This is half of 6 (the slope of Function A), so the correct answer to question 1 is the first option: Slope of Function B = 2 × Slope of Function A.
For the second problem, substitute m and b in y = mx + b according to the graph. b is the y-intercept (the point at which the line intersects the y-axis); it is (0, -4), or -4. This gives us
y = mx - 4
We must now find m. Follow the same steps above to find slope. Our two points are (-2, 0) and (0, -4).
y₁ - y₂ / x₁ - x₂
0 - (-4) / -2 - 0
0 + 4 / -2
4 / -2
-2
Substitute.
y = -2x - 4
The first option is the correct answer.
Answer:
Not a function.
Does not pass vertical line test.
B.
Step-by-step explanation:
Something called a vertical line test is used to determine if a relation that has been graphed is a function or not.
We say if it passes then it is a function.
It will pass if you are able to draw infinitely many vertical lines covering the whole graph and each vertical line either touches your relation once or none.
If a single vertical line that you draw touches more than once, then it isn't a function.
When I say draw, I don't mean you should physically do it, but more so imagine it.
Now this particular relation is not a function because I can find a vertical line that touches more than once. Take the vertical line x=5 for example.
It will touch at (5,-6) and (5,6). You cannot have an x assigned to more than one y.
From the right hand side, we will need to find a way to rewriting 3x²y in terms of cube roots.
We know that 27 is 3³, so if we were to rewrite it in terms of cube roots, we will need to multiply everything by itself two more twice. (ie we can rewrite it as ∛(3x²y)³)
Hence, we can say that it's:
![\sqrt[3]{162x^{c}y^{5}} = \sqrt[3]{(3x^{2}y)^{3}} * \sqrt[3]{6y^{d}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162x%5E%7Bc%7Dy%5E%7B5%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%283x%5E%7B2%7Dy%29%5E%7B3%7D%7D%20%2A%20%5Csqrt%5B3%5D%7B6y%5E%7Bd%7D%7D)
![= \sqrt[3]{162x^{6}y^{3+d}}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B162x%5E%7B6%7Dy%5E%7B3%2Bd%7D%7D)
Hence, c = 6 and d = 2
Answer:
2,003,160
Step-by-step explanation:
We can see the key word greater and know to add.
If someone mixes 36 liters of orange juice and 45 liters of soda water, how many batches would they make?
1,620,757 + 382,403 = 2,003,160
