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frutty [35]
3 years ago
13

Picture attached on the file

Mathematics
1 answer:
AveGali [126]3 years ago
4 0

Answer:

89/3

Stp/lanation:

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What is the slope of the line?
Hunter-Best [27]

Answer:

<h3>☘ QUESTION☘</h3>

What is the slope of the line?

-3x+5y=2x+3y

<h3>☘ ANSWER☘</h3>

-3x+5y=2x+3y → 2y = 5x → y = (5/2)x.

There are infinitely many ordered pairs that satisfy -3x+5y=2x+3y.

<h3>Answer: C.5/2</h3>

Step-by-step explanation:

✨ BRAINLY FAST ✨

✨BY#NICHOLE✨

7 0
2 years ago
80 POINTS AND BRAINLIEST TO BEST ANSWER
g100num [7]

Answer:

1. c

2. h

3. f

4. e

5. g

6. c

7. b

8. a

Step-by-step explanation:

I can go more in depth if you'd like!

3 0
3 years ago
Read 2 more answers
For geometry:(<br><br> i’ll give a brainist!!!
kvasek [131]
<h3>Answer: Angle Q = 133 degrees</h3>

========================================================

Work Shown:

Recall that for any triangle, the three angles always add to 180

P+Q+R = 180

(x+13) + (10x+13) + (2x-2) = 180

(x+10x+2x) + (13+13-2) = 180

13x+24 = 180

13x = 180-24

13x = 156

x = 156/13

x = 12

Now that we know x, we can find the angle measures

  • angle P = x+13 = 12+13 = 25 degrees
  • angle Q = 10x+13 = 10*12+13 = 120+13 = 133 degrees
  • angle R = 2x-2 = 2*12-2 = 24-2 = 22 degrees

As a way to check if we have the right answer or not, we see that,

P+Q+R = 25+133+22 = 180

So the answer is confirmed.

4 0
3 years ago
A heron is perched in a tree 50 feet above sea level. Directly below the heron, a pelican is flying 17 feet above sea level. Dir
loris [4]

Answer:

False

Step-by-step explanation:

This is because there both above sea level and 50-17=33 not -33

4 0
3 years ago
An operations analyst counted the number of arrivals per minute at an ATM in each of 30 randomly chosen minutes. The results wer
liraira [26]

Step-by-step explanation:

since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

\hat{\lambda}=\bar{x}=\frac{\sum x}{n}=\frac{30}{30}=1

So probabaility for \mathrm{X}=1 is

P(X=1)=\frac{e^{-\lambda} \lambda^{x}}{x !}=\frac{e^{-1} \cdot 1^{1}}{1 !}=0.3679

So expected frequency for X=1 is 0.3679^{*} 30=11.037 (or \left.11.04\right) .

8 0
3 years ago
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