Answer:
could you include a pic please?
Answer:
Area Of a Right Angled∆
=><em><u> </u></em><em><u>1</u></em><em><u>/</u></em><em><u>2</u></em><em><u> </u></em><em><u>x </u></em><em><u>Base </u></em><em><u>x </u></em><em><u>Height</u></em>
Area of a ∆ Using Heron's Formula
=>
Where
- S = Semiperimeter
- a ,b& c = sides of the ∆
Answer:
5/54
Step-by-step explanation:
probability of the dice being 5 = 1/6
probability of the dice being a factor of 6 = 4/6
probability of the dice being more than 1 = 5/6
1/6 * 4/6 = 4/36
4/36 * 5/6 = 20/216
20/216 simplified to lowest is equal to 5/54
Answer:
JL = 70
Step-by-step explanation:
Since K is the midpoint of JL then JK = KL and
JL = JK + KL = 9x - 1 + 2x + 27 = 11x + 26
solve for x using JK = KL
9x - 1 = 2x + 27 ( subtract 2x from both sides )
7x - 1 = 27 ( add 1 to both sides )
7x = 28 ( divide both sides by 7 )
x = 4, hence
JL = 11x + 26 = (11 × 4 ) + 26 = 44 + 26 = 70
