1 is 4 times greater than 1/4
If you multiply 1/4 by 4 you get 1
We can set it up like this, where <em>s </em>is the speed of the canoeist:

To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):
![s(s-5)[\frac{18}{s} + \frac{4}{s-5} = 3] \\ 18(s-5)+4s=3s(s-5) \\ 18s - 90+4s=3 s^{2} -15s](https://tex.z-dn.net/?f=s%28s-5%29%5B%5Cfrac%7B18%7D%7Bs%7D%20%2B%20%5Cfrac%7B4%7D%7Bs-5%7D%20%3D%203%5D%20%5C%5C%2018%28s-5%29%2B4s%3D3s%28s-5%29%20%5C%5C%2018s%20-%2090%2B4s%3D3%20s%5E%7B2%7D%20-15s)
If we rearrange this, we can turn it into a quadratic equation and factor:

Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater." We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.

The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.
To solve, set an equation:
472=0.8x
Divide both sides by 0.8
472/0.8=0.8x/0.8
x=590
Answer: The original price was $590
Answer:
0.2916, 0.1488, 0.0319
Step-by-step explanation:
Given that a sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to have oil added.
Since each trial is independent there is a constant probability for any random car to need oil is 0.10
Let X be the number of cars that need oil
A) Here X is BIN(4,0.1)

B) Here X is Bin (8, 0.1)

C) Here X is Bin (20,5)
