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Butoxors [25]
2 years ago
13

HELP ASAP! Subtract. Write your answer in simplest form.

Mathematics
2 answers:
xeze [42]2 years ago
7 0

Answer:

6/13

Step-by-step explanation:

vekshin12 years ago
6 0

Answer:

Option A=  6/13  

Step-by-step explanation:

(8-2)/ 13 = 6/13

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Identify the real numbers.<br><br>.009<br>0.63<br>1.54<br>.987<br>3.14<br>0.10​
Shkiper50 [21]
I’m pretty sure they all are real numbers-
4 0
3 years ago
In the square below the four quarter circles are congruent. find the area of the shaded region.
Alexus [3.1K]
The quarter circle pieces are all congruent allowing us to glue them together to form a circle. The circle will be completely inside the square. This circle is as large as possible so it's not spilling outside of the square. 

The area of the square is 8*8 = 64 square units

The circle has a radius of 8/2 = 4 units. Use r = 4 and plug this into the area of a circle formula
A = pi*r^2
A = pi*4^2
A = pi*16
A = 16pi

Now subtract the two areas
(area of square) - (area of circle) = 64 - 16pi

The exact answer, in terms of pi, is 64 - 16pi

If your teacher wants you to find the approximate decimal version, then you would use a calculator to find that 64 - 16pi = 13.7345175 approximately. If you end up going with the approximate answer, be sure to follow the instructions on what your teacher wants with rounding.
5 0
3 years ago
Find the quotient.<br><br> 35.4 ÷ 0.59
AleksandrR [38]

Answer:

35.4÷ 0.59=60

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The expression 32−48 factored using the GCF is <br> .
Ulleksa [173]

Answer:

Step-by-step explanation:

The largest factor that will divide evenly into both 32 and 48 is 16.

Thus, 32 - 48 = 16(2 - 3), or 16 (-1), or just -16.

Are you sure there wasn't more to this problem?

3 0
4 years ago
Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim
vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}

Dividing we get,

2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}

Adding, we have,

2 { h } 54 \text { min }=2.9 {h}

Thus, the total time taken by Joshua is 2.9 {h}

To determine the average speed we use the formula,

speed=\frac{distance}{time}

where distance=7250 and time=2.9

Hence, substituting the values we have,

speed=\frac{7250}{2.9}

Dividing, we get,

speed=2500

Thus, the average speed of Joshua during that time is 2500 m/h.

5 0
3 years ago
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