Answer:
0.6 Liters of coolant should be drained and 0.6 Liter of water should be added.
Explanation:
Volume of the radiator = 3.6 L
Percentage of antifreeze = 60%
Total volume of anti freeze in radiator = 60% of 3.6 L :
Percentage of water= 40%
Given,optimal cooling of the engine is obtained with only 50% antifreeze.
So, now we want to reduce the percentage of antifreeze from 60% to 50 %
Volume of coolant removed = x
Volume of water added = x
Volume of anti freeze removed = 60% of(x) = 0.6x
Volume of antifreeze left in radiator =50% of 3.6 L = 
1.8 Liter is the desired volume of the antifreeze.
Total volume - Removed volume = desired volume
2.16 L - 60% of( x) = 1.8 L
0.6 Liters of coolant should be drained and 0.6 Liter of water should be added.
Answer:
B
Explanation:
The Niels Bohr's atomic model superior to all the earlier models is because it showed how the electron could orbit the nucleus without falling into it
Answer:
Oxygen and Carbon are in the non-metal section. Both are in 2nd period while Carbon is in group 4A and Oxygen is in group 6A.
Oxygen has more valence electrons than carbon. I wish I could give you a more accurate explanation why on paper, but all you need to do is count the electrons on the largest shell.
Here's the orbital notation of Carbon: 1s^2 2s^2 2px^1 py^1
Carbon's largest shell is 2. Count the electrons on shell 2, and you get 4 valence electrons.
Orbital notation of Oxygen: 1s^2 2s^2 2px^2 py^1 pz^1
Oxygen's largest shell is 2. So, like with carbon, count the electrons on the largest shell. You get 6.
There is a way easier way of interpreting this where you do not even have to write the orbital notation. I wish I can explain, but just know the periods and the group numbers.
Some forces can be shear gravity and compression that are putting force on the bed
