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kow [346]
3 years ago
14

Find the inverse of the function. Show work. g(x)= - 3/x-2 +2

Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0

Answer:

\displaystyle g^{-1}(x)=\frac{-7+2x}{x-2}

Step-by-step explanation:

We are given the function:

\displaystyle g(x)=-\frac{3}{x-2}+2

Let's find the inverse of g.

Call y=g(x):

\displaystyle y=-\frac{3}{x-2}+2

We need to solve for x. Multiply both sides by x-2 to eliminate denominators:

y(x-2)=-3+2(x-2)

Operate:

yx-2y=-3+2x-4

Collect the x's to the left side and the rest to the right side of the equation:

yx-2x=-3-4+2y

Factor the left side and operate on the right side:

x(y-2)=-7+2y

Solve for x:

\displaystyle x=\frac{-7+2y}{y-2}

Interchange variables:

\displaystyle y=\frac{-7+2x}{x-2}

Call y as the inverse function:

\boxed{\displaystyle g^{-1}(x)=\frac{-7+2x}{x-2}}

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vova2212 [387]

Answer:

It would be an arithmetic sequence.

Step-by-step explanation:

This is because during each minute, he does another 2 problems. Or, in other words +2 each minute.

This is the result of the sequence during each minute:

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Time (Minutes) --->

If it was instead a geometric equation, it would go by a multiple, such as the number 2. Or, ×2 each minute.

During the first minute, he learns 2 problems. But then as each minutes passes it turns into 4, then 8, and etc..

This is the result of the pretend sequence during each minute:       (Problems Left): <em>30, 28, 24, 16, 0</em>

Time (Minutes) --->

The formula would be for this equation would follow

an = a1 + (n-1)d

an is your result.

a1 is the first number you plug in

(n-1) is just there, don't mind it (aka: the term position).

and d is the rate.

So just plug them in from your equation, and you would get this:

an = 30(n-1)2

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2 years ago
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denis-greek [22]

Answer:

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Step-by-step explanation:

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4x2/9
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