Question

Find the inverse of the function. Show work. g(x)= - 3/x-2 +2

Answer 1

Answer:

$\displaystyle g^{-1}(x)=\frac{-7+2x}{x-2}$

Step-by-step explanation:

We are given the function:

$\displaystyle g(x)=-\frac{3}{x-2}+2$

Let's find the inverse of g.

Call y=g(x):

$\displaystyle y=-\frac{3}{x-2}+2$

We need to solve for x. Multiply both sides by x-2 to eliminate denominators:

$y(x-2)=-3+2(x-2)$

Operate:

$yx-2y=-3+2x-4$

Collect the x's to the left side and the rest to the right side of the equation:

$yx-2x=-3-4+2y$

Factor the left side and operate on the right side:

$x(y-2)=-7+2y$

Solve for x:

$\displaystyle x=\frac{-7+2y}{y-2}$

Interchange variables:

$\displaystyle y=\frac{-7+2x}{x-2}$

Call y as the inverse function:

$\boxed{\displaystyle g^{-1}(x)=\frac{-7+2x}{x-2}}$