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3 years ago

How many moles is 17.6 g NaOH?

Chemistry

1 answer:

NeX [460]3 years ago

8 0

Answer: The answer is 39.99711.

Explanation:

How many grams NaOH in 1 mol? The answer is 39.99711.

We assume you are converting between grams NaOH and mole.

You can view more details on each measurement unit:

molecular weight of NaOH or mol

This compound is also known as Sodium Hydroxide.

The SI base unit for amount of substance is the mole.

1 grams NaOH is equal to 0.025001806380511 mole.

Note that rounding errors may occur, so always check the results.

Use this page to learn how to convert between grams NaOH and mole.

Type in your own numbers in the form to convert the units!

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Convert grams

NaOH

to moles

Quick conversion chart of grams NaOH to mol

1 grams NaOH to mol = 0.025 mol

10 grams NaOH to mol = 0.25002 mol

20 grams NaOH to mol = 0.50004 mol

30 grams NaOH to mol = 0.75005 mol

40 grams NaOH to mol = 1.00007 mol

50 grams NaOH to mol = 1.25009 mol

100 grams NaOH to mol = 2.50018 mol

200 grams NaOH to mol = 5.00036 mol

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Starting with a 6.847 M stock solution of HNO3, five standard solutions are prepared via serial dilution. At each stage, 25.00 m

stiks02 [169]

Answer: The concentration of $HNO_3$ in the final solution is 0.006688 M and number of moles are 0.00006688

Explanation:

According to the neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock solution = 6.847 M

$V_1$ = volume of stock solution = 25.00 ml

$M_2$ = molarity of ist dilute solution = ?

$V_2$ = volume of first dilute solution = 100.0 ml

$6.847\times 25.00=M_2\times 100.0$

$M_2=1.712M$

2) on second dilution;

$1.712\times 25.00=M_2\times 100.0$

$M_2=0.4280M$

3) on third dilution

$0.4280\times 25.00=M_2\times 100.0$

$M_2=0.1070M$

4) on fourth dilution

$0.1070\times 25.00=M_2\times 100.0$

$M_2=0.02675M$

5) on fifth dilution

$0.02675\times 25.00=M_2\times 100.0$

$M_2=0.006688M$

Thus the concentration of $HNO_3$ in the final solution is 0.006688 M

moles of $HNO_3$ = $Molarity\times {\text {Volume in L}}=0.006688\times 0.01L=0.00006688moles$

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4 years ago

Where are metals atoms located on the periodic table? where are non-metal atoms located on the periodic table?

weeeeeb [17]

Metals atoms are located on group 1 & 2 while non- metals atom on group 4 to 8

7 0

3 years ago

Based on the following information, Cl2(g) + 2 e- → 2 Cl-(aq) E° = + 1.36 V Mg2+(aq) + 2 e- → 2 Mg(s) E° = -2.37 V which of the

Alex

Answer:

D) Mg(s)

Explanation:

We are given:

$E^o_{(Cl_2/Cl^-)}= 1.36V\\E^o_{(Mg^{2+}/Mg)}=-2.37V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, chlorine will undergo reduction reaction will get reduced. Magnesium will undergo oxidation reaction and will get oxidized.

<u>Reducing agents are the species which reduces others and oxidizes itself. Thus, Magnesium will be the strongest reducing agent.</u>

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4 years ago

What is 3.5x10^2 x 8.0x10^-2 in scientific notation

docker41 [41]

Scientific notation is defined as writing a number between 0 to 10 multiplied by a power of 10
3.5 x 10² x 8.0 x 10⁻²
when we solve the equation
answer - 28
to write in scientific notation the decimal point should come after the first digit from the right. to bring the decimal point from after digit 8 to after digit 2, we have to move one decimal place to the left. then we get 2.8, to get the value as 28 we have to multiply 2.8 by 10
therefore answer is
2.8 x 10¹

6 0

3 years ago

A gas sample is held at constant pressure. The gas occupies 2.97 L of volume when the temperature is 21.6°C. Determine the tempe

STALIN [3.7K]

Answer:

339.2K

Explanation:

Using Charles law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

V1 = 2.97 L

V2 = 3.42 L

T1 = 21.6°C = 21.6 + 273 = 294.6K

T2 = ?

Using V1/T1 = V2/T2

2.97/294.6 = 3.42/T2

Cross multiply

2.97 × T2 = 294.6 × 3.42

2.97T2 = 1007.532

T2 = 1007.532 ÷ 2.97

T2 = 339.236

The final temperature is 339.2K

5 0

3 years ago