Answer:
A solid
Explanation:
A solid will stay the way it is unless melted
Answer:
1.86% NH₃
Explanation:
The reaction that takes place is:
- HCl(aq) + NH₃(aq) → NH₄Cl(aq)
We <u>calculate the moles of HCl that reacted</u>, using the volume used and the concentration:
- 32.27 mL ⇒ 32.27/1000 = 0.03227 L
- 0.1080 M * 0.03227 L = 3.4852x10⁻³ mol HCl
The moles of HCl are equal to the moles of NH₃, so now we <u>calculate the mass of NH₃ that was titrated</u>, using its molecular weight:
- 3.4852x10⁻³ mol NH₃ * 17 g/mol = 0.0592 g NH₃
The weight percent NH₃ in the aliquot (and thus in the diluted sample) is:
- 0.0592 / 12.949 * 100% = 0.4575%
Now we <u>calculate the total mass of NH₃ in the diluted sample</u>:
Diluted sample total mass = Aqueous waste Mass + Water mass = 23.495 + 72.311 = 95.806 g
- 0.4575% * 95.806 g = 0.4383 g NH₃
Finally we calculate the weight percent NH₃ in the original sample of aqueous waste:
- 0.4383 g NH₃ / 23.495 g * 100% = 1.86% NH₃
Answer:
<h3>your question :</h3>
how to rapidly separate red#40 from ZnO
<h3>answer :</h3>
Red #40 is soluble in water while zinc oxide is not. 4- heat the solution of red #40 and water until water evaporates and red#40 remains
hope it's help
<h3>#carryONlearning </h3>
If organisms cannot adapt to the changes in their ecosystem, they may move to another location. If they will not move, the species may become threatened, endangered or extinct.
<h2>
Hope it helps...</h2>
Answer:
[HCl] = 4.54 M
Explanation:
14.2 % by mass is 14.2 g in 100 g of solution.
Let's calculate the moles of our solute, HCl
14.2 g / 36.45 g/mol = 0.389 mol
Molarity is mol/L (moles of solute in 1L of solution)
Let's determine the volume of solution with density
Solution density = Solution mass / Solution volume
Solution volume = Solution mass / Solution density
Solution volume = 100 g / 1.1684 g/mL → 85.6 mL
For molarity, we need the volume in L. Let's make the unit change.
85.6 mL . 1 L/1000mL = 0.0856L
Molarity is 0.389 mol / 0.0856L → 4.54 M
