Answer: C) middle 50 percent of the data
The interquartile range (IQR) spans from the first quartile Q1 to the third quartile Q3.
25% of the data is below Q1 and 75% of the data is below Q3. The gap between the two endpoints consists of 75-25 = 50 percent of the data, or half of the data.
Answer:
3853 g
Step-by-step explanation:
M_r: 107.87
16Ag + S₈ ⟶ 8Ag₂S; ΔH°f = -31.8 kJ·mol⁻¹
1. Calculate the moles of Ag₂S
Moles of Ag₂S = 567.9 kJ × 1 mol Ag₂S/31.8kJ = 17.858 mol Ag₂S
2. Calculate the moles of Ag
Moles of Ag = 17.86 mol Ag₂S × (16 mol Ag/8 mol Ag₂S) = 35.717 mol Ag
3. Calculate the mass of Ag
Mass of g = 35.717 mol Ag × (107.87 g Ag/1 mol Ag) = 3853 g Ag
You must react 3853 g of Ag to produce 567.9 kJ of heat
Answer:
a. True
b. True
c. False
d. True
Explanation:
a). A a very low substrate concentration , 
. Thus according to the Machaelis-Menten equation becomes
![$V_0 = \frac{V_{max} \times [S]}{Km}$](https://tex.z-dn.net/?f=%24V_0%20%3D%20%5Cfrac%7BV_%7Bmax%7D%20%5Ctimes%20%5BS%5D%7D%7BKm%7D%24)
Here since the 
varies directly to the substrate concentration [S], the initial velocity is lower than the maximal velocity. Thus option (a) is true.
b). The Michaelis -Menten kinetics equation states that :
![$V_0 = \frac{V_{max} \times [S]}{Km+[S]}$](https://tex.z-dn.net/?f=%24V_0%20%3D%20%5Cfrac%7BV_%7Bmax%7D%20%5Ctimes%20%5BS%5D%7D%7BKm%2B%5BS%5D%7D%24)
Here the initial velocity changes directly with the substrate concentration as is directly proportional to [S]. But 
is same for any particular concentration of the enzymes. Thus, option (b) is true.
c). As the substrate concentration increases, the initial velocity also increases. Thus option (c) is false.
d). Option (d) explains the procedures to estimate the initial velocity which is correct. Thus, option (d) is true.
Since glycolysis of one glucose molecule generates two acetyl CoA molecules, the reactions in the glycolytic pathway and citric acid cycle produce six CO2 molecules, 10 NADH molecules, and two FADH2 molecules per glucose molecule
