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nalin [4]
3 years ago
6

A gas sample is held at constant pressure. The gas occupies 2.97 L of volume when the temperature is 21.6°C. Determine the tempe

rature at which the volume of the gas is 3.42 L. (Charles')
Chemistry
1 answer:
STALIN [3.7K]3 years ago
5 0

Answer:

339.2K

Explanation:

Using Charles law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

V1 = 2.97 L

V2 = 3.42 L

T1 = 21.6°C = 21.6 + 273 = 294.6K

T2 = ?

Using V1/T1 = V2/T2

2.97/294.6 = 3.42/T2

Cross multiply

2.97 × T2 = 294.6 × 3.42

2.97T2 = 1007.532

T2 = 1007.532 ÷ 2.97

T2 = 339.236

The final temperature is 339.2K

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Answer: Option D is correct.

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\lambda =\frac{h}{mv}

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h = Planck's constant

m = mass of the particle

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3 years ago
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Answer: 37

Explanation:

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Fill in the coefficients that will balance the following reaction: a0Na + a1H2O → a2NaOH + a3H2
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Hey there !  :

<span>2 Na + 2 H2O = 2 NaOH + 1 H<span>2

</span></span>Sodium<span> + </span>Dihydrogen Monoxide<span> = </span><span>Natriumhydroxid</span><span> + </span>Hydrogen

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