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SCORPION-xisa [38]
3 years ago
13

How can absolute value help you understand the size of a quantity? Give an example.

Mathematics
2 answers:
Eduardwww [97]3 years ago
3 0
I hope this helps you

Elden [556K]3 years ago
3 0
The x is the absolute value so the x is the unknown number....
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Todd placed 32 square tiles along the edge of his wooden dining room table, as shown below. Note: Figure is not drawn to scale.
Flauer [41]

Answer:

The diagonal is 421.

Step-by-step explanation:

This is a difficult question. To find the diagonal, you need to find the base and the height of the square. After that, you need to make it a triangle, by using this equation; A=\frac{1}{2} BH (A being area, B being base, and H being height) then find the length of the hypotenuse of the triangle, which I will do for you.

32*13=416 The B and H = 416. Plug it into the equation now;

A=\frac{1}{2}(416*416)\\\\\\A=\frac{1}{2} 173,056\\\\\\A=86,528Now that you have done that, we know that the area of our new triangle is 86,528.

The diagonal is: 421

8 0
3 years ago
Read 2 more answers
Ticket
NARA [144]

Answer:

The rearrangement can be 45, 987 , 310

Step-by-step explanation:

Here, we want to rearrange the number such that 9 is worth 10 times as what it is worth presently

The value of 9 presently is 90,000

So 10 times as worth will be 10 * 90,000 = 900,000

So we can have the new arrangement as;

45, 987, 310

3 0
3 years ago
Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

From the question

a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

8 0
2 years ago
6-11x=7x-12 how do you solve
tekilochka [14]
Use Cymath it helps and give u the answer
6 0
3 years ago
What is one plus one<br>​
inna [77]

Answer:

2

Step-by-step explanation:

21 lol

7 0
3 years ago
Read 2 more answers
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