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3 years ago

2 Na + Cl2 → 2 NaCl

Chemistry

2 answers:

Ksivusya [100]3 years ago

8 0

Approximately 71.77 grams. I think so

Mademuasel [1]3 years ago

8 0

Grams of Cl₂ needed : 71.781 g

<h3>Further explanation</h3>

Reaction

2 Na + Cl₂ → 2 NaCl

mass of Na = 46.5 g

mol of Na(Ar=23 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{46.5}{23}=2.021$

From equation, mol ratio of Na : Cl₂ = 2 : 1, so mol Cl₂ :

$\tt \dfrac{1}{2}\times 2.021=1.011$

Mass of Cl₂(MW=71 g/mol) :

$\tt mass=mol\times MW\\\\mass=1.011\times 71\\\\mass=71.781~g$

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6 0

3 years ago

The balanced equation for the reaction of ammonia and oxygen is the following. 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) The stand

ale4655 [162]

Answer:

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Explanation:

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3 years ago

How many grams of h2 will be produced if 175g of HCI are allowed to react completely with sodium

Sedbober [7]

Answer:

4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium

Explanation:

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) you can see that the following amounts in moles of each compound react and are produced:

HCl: 2 moles
Na: 1 mole
NaCl: 2 moles
H₂: 1 mole

You know the following masses of each element:

H: 1 g/mole
Cl: 35.45 g/mole
Na: 23 g/mole

So, the molar mass of each compound participating in the reaction is:

HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
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Then, by stoichiometry of the reaction, the following amounts in grams of each of the compounds participating in the reaction react and are produced:

HCl: 2 moles* 36.45 g/mole= 72.9 g
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So, a rule of three applies as follows: if by stoichiometry, when reacting 72.9 grams of HCl 2 grams of H₂ are formed, when reacting 175 grams of HCl how much mass of H₂ will be formed?

$mass of H_{2} =\frac{175 g of HCl*2g ofH_{2} }{72.9 g of HCl}$