Question

A second-order reaction has a half-life of 12 s when the initial concentration of reactant is 0.98 M. The rate constant for this reaction is __________ M-1s-1.

Answer 1

Answer:

0.085 (Ms)⁻¹

Explanation:

Half life = 12 s

$[A_o]$ is the initial concentration = 0.98 M

Half life expression for second order kinetic is:

$t_{1/2}=\frac{1}{k[A_o]}$

So,

$12=\frac{1}{k\times 0.98}$

$x=\frac{25}{294}$

k = 0.085 (Ms)⁻¹

The rate constant for this reaction is 0.085 (Ms)⁻¹ .