Given that the population has been modeled by the formula:
a=118e^(0.024t), the time taken for the population to hit 140k will be given by:
140000=118e^(0.024t)
solving for t we shall have:
140000/118=e^(0.024t)
thus;
0.024t=ln(140000/118)
t=1/0.024*ln(140000/118)
t=295
thus the time the population will be 140000 will be:
1998+295
=2293
Answer:
Part A: (0.75 + .25 + .60) - .20 = 1.40
Part B : Addition and subtraction ¯\(°_o)/¯
First parentheses ¯\(°_o)/¯
Then subtract
¯\(°_o)/¯
Answer:
95435.20 miles
Step-by-step explanation:
just add them both together
Answer:
a) 
b) The should sample at least 293 small claims.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so
, which means that the answer of question a is z = 1.645.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?
They should sample at least n small claims, in which n is found when
. So







The should sample at least 293 small claims.