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3 years ago

5

The ratio of green houses to white houses on Winthrop Street is equal to 2 to 3. There are 60 white houses on Winthrop Street. H

ow many green houses are there?

1 answer:

irinina [24]3 years ago

4 0

Answer:

40

Step-by-step explanation:

White Houses: 3 x 20 = 60

Green Houses: 2 x 20 = 40

3 : 2 = 60 : 40

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Riley has collected surveys for her final thesis project. One one question, 46.1% of respondents said that conditions were impro

ira [324]

Answer:

The maximum value of the confidence interval for this set of survey results is 51.73%.

Step-by-step explanation:

A confidence interval has two bounds, a lower bound and an upper bound.

These bounds depend on the sample proportion and on the margin of error.

The lower bound is the sample proportion subtracted by the margin of error.

The upper bound is the margin of error added to the sample proportion.

In this question:

Sample proportion: 46.1%

Margin of error: 5.63%.

Maximum value is the upper bound:

46.1+5.63 = 51.73

The maximum value of the confidence interval for this set of survey results is 51.73%.

5 0

3 years ago

13 points plz help I need a for real answer

arsen [322]

(-1,8) is the correct answer I’m pretty sure

5 0

3 years ago

Statistics question about random probability Cheese pastureized or Raw MilkA cheese can be classified as either raw-milk or past

blsea [12.9K]

Answer:

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) Or Pr(RRPP) Or Pr(RRRP) Or Pr(RRRR)

= 0.1269 to 4 decimal places

It would not be unusual that at least one of four randomly selected cheeses is raw-milk, because the probability have a value between 0 and 1

Step-by-step explanation:

If is given that 80% of the cheese is classified as pasteurized.

It then implies that 20% of the cheese is classified as Raw-milk

Probability of pasteurized cheese is 0.82(Denoted by Pr(P))

Probability of raw-milk cheese is 0.18(Denoted as Pr(R))

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) + Pr(RRPP) + Pr(RRRP) + Pr(RRRR)

(0.18 x 0.82 x 0.82 x 0.82) + (0.18 x 0.18 x 0.82 x 0.82) + (0.18 x 0.18 x 0.18 x 0.82) + (0.18 x 0.18 x 0.18 x 0.18) = 0.1269 to 4 decimal places

3 0

3 years ago

Oliver is 33 years old than is son .eight years ago Oliver's age is five more than thrice his son's present age go old is Oliver

galina1969 [7]

Answer:

gonna need a bit better grammer here or i cant help

Step-by-step explanation:

i dont know

6 0

3 years ago

Which statements are true about the circle shown?

CaHeK987 [17]

Answer:

Among the five statements,statement 1 and 4 are true for the circle shown.

Step-by-step explanation:

Given:

An image is attached here.

A circle with radius = 15.4 m

We ave to find the diameter,circumference and relationship between the two.

Formula to be used:

⇒ Diameter of a circle = 2r

⇒ Circumference = 2πr

Lets find the values.

Diameter = $2r=2(15.4) = 30.8$ m
Circumference = $2\pi r =2(3.14)(15.4)=96.7$ m
Relationship = $\frac{circumference}{diameter}$ $=$ $\frac{96.7}{6}$ $=3.1$

We can say that a little more than 3 diameters could be wrapped around the circle.

From the drop down our choices are.

The diameter of the circle is 30.8 m.
The approximate circumference of the circle ,rounded to the nearest tenth is 96.7 m.

Option 1 and 4 are the right choices.

8 0

4 years ago