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son4ous [18]
3 years ago
6

Based on the data, which of the following explains the relationship between the distance of the planet from the Sun and its plan

etary motion around the sun?
A. The planets with the least distance from the sun experience a longer time of revolution and shorter days of rotation.

B. The planets with the least distance from the sun experience a shorter time of revolution and shortest days of rotation.

C. The planets with the greatest distance from the sun experience a longer time of revolution and longer days of rotation.

D. The planets with the greatest distance from the sun experience a longer time of revolution and shorter days of rotation.

Physics
2 answers:
Fofino [41]3 years ago
7 0
D the planets with the greatest
VikaD [51]3 years ago
7 0
The answer is D because the outer planets aka gas giants spin very fast what is rotation on its axis. But because the sun gravity isn’t as great to the bigger and farther away planets the have a longer revolution around the sun. Remember this revolves around the sun and rotates on axis for the planets
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Wonder Woman and Superman fly to an altitude of 1690 km , carrying between them a chest full of jewels that they intend to put i
Arturiano [62]

Answer:

5120 m/s

Explanation:

The acceleration due to gravity is:

g = MG / r²

where M is the mass of the earth, G is the universal constant of gravitation, and r is the distance from the earth's center to the object's center.

Here, r = h + R, where h is the height of the chest above the surface and R is the radius of the earth.

g = MG / (h + R)²

Acceleration is the derivative of velocity:

dv/dt = MG / (h + R)²

Using chain rule, we can say:

(dv/dh) (dh/dt) = MG / (h + R)²

(dv/dh) v = MG / (h + R)²

Separate the variables:

v dv = MG / (h + R)² dh

Integrating:

∫₀ᵛ v dv = MG ∫₀ʰ dh / (h + R)²

½ v² |₀ᵛ = -MG / (h + R) |₀ʰ

½ (v² − 0²) = -MG / (h + R) − -MG / (0 + R)

½ v² = -MG / (h + R) + MG / R

½ v² = MGh / (R(h + R))

v² = 2MGh / (R(h + R))

Given:

M = 5.98×10²⁴ kg

R = 6.37×10⁶ m

h = 1.69×10⁶ m

G = 6.67×10⁻¹¹ m³/kg/s²

Plugging in:

v² = 2 (5.98×10²⁴) (6.67×10⁻¹¹) (1.69×10⁶) / ((6.37×10⁶) (1.69×10⁶ + 6.37×10⁶))

v² = 2 (5.98) (6.67) (1.69) / ((6.37) (1.69 + 6.37)) × 10⁷

v ≈ 5120 m/s

Notice that if we had approximated g as a constant 9.8 m/s², we would have gotten an answer of:

v² = v₀² + 2a(x - x₀)

v² = (0 m/s)² + 2 (9.8 m/s²) (1.69×10⁶ m - 0 m)

v ≈ 5760 m/s

So we know that our calculated velocity of 5120 m/s is a reasonable answer.

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What is the highest you can get before reaching space and start floating
grin007 [14]
327,360 feet
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What is the mass of a person who weighs 653 N at earths surface
miss Akunina [59]

Answer:

66.6 kg

Explanation:

The weight of a person at Earth's surface is given by

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The person in the problem has a weight of

W = 653 N

Therefore, we can rearrange the equation to find his mass:

m=\frac{W}{g}=\frac{653}{9.8}=66.6 kg

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The answer is b brainlistt plz

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