Answer:
a. 17 μC b. 14.45 J
Explanation:
Here is the complete question
A pair of 10μF capacitors in a high-power laser are charged to 1.7 kV.
a. What charge is stored in each capacitor?
b. How much energy is stored in each capacitor?
a. The charge Q stored in a capacitor is Q = CV where C = capacitance and V = voltage. Here, C = 10μF = 10 × 10⁻⁶ F and V = 1.7 kV = 1.7 × 10³ V.
So, Q = CV = 10 × 10⁻⁶ × 1.7 × 10³ = 1.7 × 10⁻² C = 17 × 10⁻³ C = 17 μC
b. The energy stored in a capacitor is given by W = 1/2CV² = 1/2 × 10 × 10⁻⁶ F × (1.7 × 10³ V)² = 1/2 × 10 × 10⁻⁶ F × 2.89 × 10⁶ V² = 1/2 × 10 × 2.89 × 10⁶ × 10⁻⁶ J = 14.45 J
9.1 miles per hour because 2.2 is your hours right?
Answer:
Well a meter stick has increments of a centimeter, and since 1 cm=0.01m he should record it as 4.02m(b)
Explanation:
Answer:
15 m
Explanation:
Given,
Mass ( m ) = 75 kg
Potential energy ( P.E ) = 11,025 J
To find : Hight ( h )
Formula : -
P.E = mgh
[ Note : The value of g = 9.8 m/s² ]
h = P.E / mg
= 11,025 / ( 75 x 9.8 )
= 11,025 / 735
h = 15 m
Hence,
15 m is the high off the ground must you be if you mass is 75 kg and you have 11,025 J of energy stored inside.
