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Vadim26 [7]
3 years ago
15

A person running has a momentum of 720 kg m/s and is traveling at a velocity of 5 m/s. What is his mass?

Physics
1 answer:
allsm [11]3 years ago
7 0

Explanation:

Momentum is mass times velocity.

p = mv

720 kg m/s = m (5 m/s)

m = 144 kg

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An electron in a television tube is accelerated uniformly from rest to a speed of 8.4\times 10^7~\text{m/s}8.4×10 ​7 ​​ m/s over
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Answer:

P=3.42×10^-6 J/s

Explanation:

From the kinematics of motion with constant acceleration we know that :  

vf^2=vi^2+2*a(xf-xi)

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• a is the acceleration of the electron  

• xf , xi are the final and the initial position of the electron .

Strategy for solving the problem : at first from the given information we calculate the acceleration of the electron.  

Givens: vf = 8.4 x 10^7 m/s , vi, = 0 m/s , xf = 0.025 m and xi = 0 m  

vf^2 =vi^2+2*a(xf-xi)

vf^2-vi^2=2*a(xf-xi)

2*a(xf-xi)= vf^2-vi^2

          a = (vf^2-vi^2)/2(xf-xi)

Pluging known information to get :

a = (vf^2-vi^2)/2(xf-xi)

  = 1.411 × 10^17

From the acceleration and the previous Eq. we can calculate the final velocity of the electron but a new position xf = 0.01 m  

so,

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vf^2 =5.312× 10^7

From the following Eq. we can calculate the time elapsed in this motion .  

xf =xi+vi*t+1/2*a*t

xf =xi+vi*t+1/2*a*t

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now we can use the power P Eq.  

 P=W/Δt => ΔK/Δt  

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P=1/2*m*vf^2-1/2*m*vi^2/Δt

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6 0
2 years ago
Please Help
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A positive charge is moved from point A to point B along an equipotential surface. How much work is performed or required in mov
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Answer:

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Explanation:

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