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3 years ago

B) What is the value of 3V125 ?

Mathematics

2 answers:

AVprozaik [17]3 years ago

6 0

Answer: 5

Step-by-step explanation: 5 x 5 x 5 = 125 and since your finding the cubed root of 125, there are supposed to be 3 numbers you multiply that are the same. This is why the answer is 5. Plus, Roots are the inverse operation of exponents.

Assoli18 [71]3 years ago

4 0

Answer: 5

Explanation:

Cube root (125) = Cube root(5^3) = 5

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Answer:

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3 years ago

Three students had $12.00 total and went to a snack bar where their bill was $8.57. They want to share equally the money that is

tamaranim1 [39]

Answer:

1.14

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4 years ago

7-5(2x+14)= -2(x+63)

jeka94

7-5(2x+14)= -2(x+63)

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6 0

3 years ago

In △ABC acute angles are in the ratio 5:1, i.e. ∠BAC:∠ABC = 5:1. If CH is an altitude and CL is an angle bisector, find m∠HCL.

tekilochka [14]

If $m\angle BAC:m\angle ABC=5:1,$ then $m\angla BAC=(5x)^{\circ},\ m\angle ABC=x^{\circ}.$

The sum of the measures of the interior angles of the triangle is always 180°, then

$m\angle ACB=180^{\circ}-x^{\circ}-(5x)^{\circ}=180^{\circ}-(6x)^{\circ}.$

Since CL is bisector, then

$m\angle BCL=m\angle ACL=\dfrac{180^{\circ}-(6x)^{\circ}}{2}=90^{\circ}-(3x)^{\circ}.$

Consider right triangle ACH. In this triangle

$m\angle ACH=180^{\circ}-90^{\circ}-(5x)^{\circ}=90^{\circ}-(5x)^{\circ}.$

Now angle HCL has measure

$m\angle HCL=m\angle ACL-m\angle ACH=90^{\circ}-(3x)^{\circ}-(90^{\circ}-(5x)^{\circ})=(2x)^{\circ}=2m\angle ABC.$

Answer: $m\angle HCL=2m\angle ABC.$

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4 years ago