A car’s velocity changes from 35 m/s to stopped in 13 seconds. Calculate acceleration.

Physics

1 answer:

padilas [110]3 years ago

5 0

Answer:

Acceleration = 3m/s^2

Vf= 0 Vi =35m/s t= 13s

Explanation:

$Acceleration = \frac{Change in velocity}{Change in time}\\ = \frac{35m/s}{13s}\\ a = 2.69m/s^2\\ a = 2.7m/s^2\\ a = 3m/s^2$

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