2 years ago

A car’s velocity changes from 35 m/s to stopped in 13 seconds. Calculate acceleration.

Physics

1 answer:

padilas [110]2 years ago

5 0

Answer:

Acceleration = 3m/s^2

Vf= 0 Vi =35m/s t= 13s

Explanation:

$Acceleration = \frac{Change in velocity}{Change in time}\\ = \frac{35m/s}{13s}\\ a = 2.69m/s^2\\ a = 2.7m/s^2\\ a = 3m/s^2$

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Lubov Fominskaja [6]

Answer:

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As per the question:

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Now,

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Now,

Suppose the distance from the radio station be 'r' from where the intensity of the photon is $1\ photon/s/m^{2}$

$I_{p} = \frac{n}{A} = \frac{n}{4\pi r^{2}}$

$1 = \frac{8.836\times 10^{31}}{4\pi r^{2}}$

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Now,

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1 ly = $9.4607\times 10^{15}\ m$

Thus

$r = \frac{2.65\times 10^{15}}{9.4607\times 10^{15}} = 0.28\ ly$

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3 years ago

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3 years ago

What volume (in liters) of gasoline has a total heat of combustion equal to the energy obtained in part (a)? (see section 17.6;

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<h3><u>Answer;</u></h3>

volume = 6.3 × 10^-2 L

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3 years ago