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labwork [276]
3 years ago
15

What can accurately be said about a resultant wave that displays both reinforcement and interference?        A. Molecules remain

in their normal positions at spots of reinforcement.   B. Maximum interference occurs where the troughs of the two component waves are in phase.   C. The crests of the two component waves are in phase where interference occurs in the resultant wave.   D. The component waves have different frequencies.
Physics
2 answers:
never [62]3 years ago
6 0

Answer;

D. The component waves have different frequencies.

Explanation;

-Interference is a property of waves that results from combination of two or more wave trains moving on intersecting or coincident paths. This effect results to the addition of the amplitudes of the individual waves at each point affected by more than one wave.

-When two waves are of the same frequency and are in phase (which means; they vibrate at the same rate and are maximum at the same time), the wave amplitudes are reinforced, producing constructive interference.

-Conversely, when two waves are out of phase by half period (meaning that one is minimum when the other is maximum), the result is destructive interference, producing complete annulment if they are of equal amplitude.

Alchen [17]3 years ago
4 0
The situation that can accurately be said about a resultant wave that displays both reinforcement and interference is that crests of the two component waves are in phase. The answer is letter B.
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A 27.0-m steel wire and a 48.0-m copper wire are attached end to end and stretched to a tension of 145 N. Both wires have a radi
algol13

Answer:

The time taken by the wave to travel  along the combination of two wires is 458 ms.

Explanation:

Given that,

Length of steel wire= 27.0 m

Length of copper wire = 48.0 m

Tension = 145 N

Radius of both wires = 0.450 mm

Density of steel wire \rho_{s}= 7.86\times10^{3}\ kg/m^{3}

Density of copper wire \rho_{c}=8.92\times10^{3}\ kg/m^3

We need to calculate the linear density of steel wire

Using formula of linear density

\mu_{s}=\rho_{s}A

\mu_{s}=\rho_{s}\times\pi r^2

Put the value into the formula

\mu_{s}=7.86\times10^{3}\times\pi\times(0.450\times10^{-3})^2

\mu_{s}=5.00\times10^{-3}\ kg/m

We need to calculate the linear density of copper wire

Using formula of linear density

\mu_{c}=\rho_{s}A

\mu_{c}=\rho_{s}\times\pi r^2

Put the value into the formula

\mu_{c}=8.92\times10^{3}\times\pi\times(0.450\times10^{-3})^2

\mu_{c}=5.67\times10^{-3}\ kg/m

We need to calculate the velocity of the wave along the steel wire

Using formula of velocity

v_{s}=\sqrt{\dfrac{T}{\mu_{s}}}

v_{s}=\sqrt{\dfrac{145}{5.00\times10^{-3}}}

v_{s}=170.3\ m/s

We need to calculate the velocity of the wave along the steel wire

Using formula of velocity

v_{c}=\sqrt{\dfrac{T}{\mu_{c}}}

v_{c}=\sqrt{\dfrac{145}{5.67\times10^{-3}}}

v_{c}=159.9\ m/s

We need to calculate the time taken by the wave to travel  along the combination of two wires

t=t_{s}+t_{c}

t=\dfrac{l_{s}}{v_{s}}+\dfrac{l_{c}}{v_{c}}

Put the value into the formula

t=\dfrac{27.0}{170.3}+\dfrac{48.0}{159.9}

t=0.458\ sec

t=458\ ms

Hence, The time taken by the wave to travel  along the combination of two wires is 458 ms.

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Explanation:

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The speed of sound depends on the medium in which it is transported.

Sound travels fastest through solids, slower through liquids and slowest through gases. 

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When a river flows into an ocean, it slows down and deposits materials in its delta
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A flute player hears four beats per second when she compares her note to a 523 HzHz tuning fork (the note C). She can match the
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Answer:

527 Hz

Solution:

As per the question:

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Frequency of the tuning fork, f = 523 Hz

Now,

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\Delta f = f - f_{i}

f_{i} = f \pm \Delta f

when

f_{i} = f + \Delta f = 523 + 4 = 527 Hz

when

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But we know that as the length of the flute increases the frequency decreases

Hence, the initial frequency must be 527 Hz

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