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Sindrei [870]
3 years ago
12

Devora explored a secret cave. 48\text{ m}48 m48, start text, space, m, end text from the entrance, she found an empty chest wit

h a map drawn on it. The map showed treasure buried 95\text{ m}95 m95, start text, space, m, end text from the entrance to the cave. From the treasure, the map showed a 30\degree30°30, degree angle between the chest and the entrance, as shown below. Devora faced the entrance, then turned a certain number of degrees to her left and walked until she got to the treasure.
Mathematics
1 answer:
siniylev [52]3 years ago
3 0

Answer:

82°

Step-by-step explanation:

You might be interested in
Using suitable identity evaluate the following : 98^3
stiv31 [10]

941,192

Steps:

(a-b)^3=a^3-b^3-3a^2b+3ab

\begin{gathered} (98)^3=(100-2)^3 \\ (100-2)^{3\text{ }}=(100)^3-(2)^3-3\cdot(100)^2\cdot2+3\cdot100\cdot2^2\text{ } \\ (100)^3-(2)^3-3\cdot(100)^2\cdot2+3\cdot100\cdot2^2\text{ = 1,0}00,000\text{ - 3 - 60,000 +1,200} \\ \text{ 1,0}00,000\text{ - 3 - 60,000 +1,200 = 941,192} \end{gathered}

6 0
1 year ago
In the triangle ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC.
Basile [38]

Step-by-step Answer:

AN is height, so A is perpendicular to BC.  (See image attached).

BN = 18

AN = 24

AC = 40

All as labeled.

ABN is a right triangle, with AB = sqrt(18^2+24^2)=sqrt(324+576)=30

ACN is a right triangle, with CN = sqrt(40^2-24^2)=sqrt(1600-576) = 32

=>

BC = BN + NC = 18 + 32 = 50

8 0
3 years ago
a man sold two typewriters it 2970 each. if he gain 10% on one in 10% loss on father what is his gain or loss percent​
kipiarov [429]

original price of first typewriter = x  

2970/x = 110/100  

x = 2970 x 100/110 = 2700  

Price of first typewriter = Rs 2700  

Original price of second typewriter = y  

2970/y = 90/100  

y = 2970 x 100/90  

y = 3300  

Original price of second typewriter = 3300  

profit from first typewriter = 2970 - 2700 = 270  

Loss from second typewriter =  3300 - 2970= 330  

270 less than 330  

so he lost 330 - 270 = Rs 60 in whole transaction

3 0
3 years ago
Please help!! Which two equations are the equations of vertical asymptotes of the function y = 5∕3 tan(3∕4x)?
Margarita [4]

9514 1404 393

Answer:

  D) x = 2π∕3 and x = –2π∕3

Step-by-step explanation:

The tangent function has asymptotes at ±π/2, so the corresponding values of x are ...

  (3/4)x = ±π/2

  x = (±π/2)(4/3) = ±2π/3 . . . . matches choice D

8 0
2 years ago
Read 2 more answers
Consider the quadratic function f(x)=2x^2-8x-10
Slav-nsk [51]

Answer:

f(x) = 2x² - 8x - 10.

This is a parabola open upward (since a>0) with an axis of symmetry = -b/2a:

a) axis of symmetry: x = -(-8)/(2*2) = 8/4 = 2. Then x = 2, which is the x component of the vertex

b) for x =  2, f(x) = f(2) = - 18 (component of y of the vertex)

c) VERTEX(2, - 18)

d) DISCRIMINENT: b² - 4.a.c = 64 - 4*2*(-10) = 144

Hope this helps! :)

6 0
3 years ago
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