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svetlana [45]
3 years ago
7

A bucket holds 10 white golf balls, 3 pink golf balls, and 5 yellow golf balls. Jason selects 1 golf ball from the bucket at ran

dom.
What is the probability that the golf ball he selects is white or pink?

A. 554

B. 513

C. 1318

D. 135
Mathematics
2 answers:
Rashid [163]3 years ago
5 0
The correct answer is C, as long as there is supposed to be a slash there. ;)

Have an awesome day!
Novosadov [1.4K]3 years ago
5 0

Answer:  The correct option is (C) \dfrac{13}{18}.

Step-by-step explanation:  Given that a bucket holds 10 white golf balls, 3 pink golf balls, and 5 yellow golf balls. Jason selects 1 golf ball from the bucket at random.

We are to find the probability that the golf ball he selects is white or pink.

Here,

number of favourable cases

= no. of white balls + no. of pink balls

= 10 + 3

= 13,

And total number of cases = total no. of balls = 10 + 3 + 5 = 18.

Therefore, the required probability  that the golf ball he selects is white or pink is given by

P=\dfrac{\textup{no. of favourable cases}}{\textup{total number of cases}}\\\\\\\Rightarrow P=\dfrac{13}{18}.

Thus, the required probability is \dfrac{13}{18}.

Option (C) is correct.

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A simple random sample from a population with a normal distribution of 98 body temperatures has x =98.90 °F and s =0.68°F. Const
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Answer:

0.609 \leq \sigma \leq 0.772  

And the best conclusion would be:

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Step-by-step explanation:

1) Data given and notation  

s=0.68 represent the sample standard deviation  

\bar x =98.90 represent the sample mean  

n=98 the sample size  

Confidence=90% or 0.90  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .  

2) Calculating the confidence interval  

The confidence interval for the population variance is given by the following formula:  

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}  

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:  

df=n-1=98-1=97  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,97)" "=CHISQ.INV(0.95,97)". so for this case the critical values are:  

\chi^2_{\alpha/2}=120.990  

\chi^2_{1- \alpha/2}=75.282  

And replacing into the formula for the interval we got:  

\frac{(97)(0.68)^2}{120.990} \leq \sigma \leq \frac{(97)(0.68)^2}{75.282}  

0.371 \leq \sigma^2 \leq 0.596  

Now we just take square root on both sides of the interval and we got:  

0.609 \leq \sigma \leq 0.772  

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

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Answer:

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Step-by-step explanation:

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