I guess that's all you can do
to find a and b you need more information
b=-a -> a (x-3)-a (x-2)=3
a [x-3-(x-2)]=3
a (x-3-x+2)=3
a*(-1)=3
a=3:(-1)
a=-3
b=-a=-(-3)=3
36-(b^2+c^2-2bc)=36-(b-c)^2=6^2-(b-c)^2= (6+b-c)[6-(b-c)]=(6+b-c)(6-b+c)
Answer:
The x coordinate is 2
Step-by-step explanation:
Given


Required
Determine the x coordinate of B
Since B is the bisector of AC, then B is the midpoint and will be calculated using;

Considering the x coordinates alone;

Where
and 
Substitute values for x1 and x2



<em>Hence;</em>
<em>The x coordinate is 2</em>