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Sav [38]
3 years ago
8

frac{1}{9} + 1 \frac{1}{2} " alt="4 \frac{1}{9} + 1 \frac{1}{2} " align="absmiddle" class="latex-formula">
4 \frac{1}{2}  \div  \frac{3}{5}
need help please​
Mathematics
1 answer:
tino4ka555 [31]3 years ago
6 0

Step-by-step explanation:

\tt{ 1. \:  \: 4 \frac{1}{9} + 1 \frac{1}{2}}

⇢ \tt{  \frac{37}{9}  +  \frac{3}{2} }

⇢ \tt{ \frac{37  \times 2 + 3 \times 9}{18} }

⇢ \tt{ \frac{74 + 27}{18} }

⇢ \tt{ \frac{101}{18}}

⇢ \boxed{ \tt{5 \frac{11}{18}} }

---------------------------------------------------------

\tt{ \: 2. \:  \: 4 \frac{1}{2} \div \frac{3}{5}}

⇢ \tt{ \frac{9}{2}  \times  \frac{5}{3}}

⇢ \tt{ \frac{9  \times 5}{2 \times 3}}

⇢ \tt{ \frac{45}{6}}

⇢ \boxed{ \tt{7 \frac{3}{6}} }

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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3 years ago
Please help what is the answer if you put a link you will get reported
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3 years ago
Evaluate (picture shows equation)
PilotLPTM [1.2K]
If we try to evaluate this expression, we arrive at an indeterminate limit of the form ∞ · 0. So we rewrite this limit as
                      lim of [ e^(-x/5) / (1 / x^3) ] as x→∞
This results in an determinate form of 0/0, so we apply L'Hospital's rule by differentiating the numerator and denominator.
                      lim of [ -1/5e^(-x/5) / (-3/x^4) ] as x→∞
Multiply the numerator and denominator by x^4
                      lim of [ -1/5 * x^4 * e^(-x/5) / (-3) ] as x→∞
Since e^(-x/5) approaches 0 as x→∞, the limit evaluates to 0.
The answer to this question is 0.
7 0
3 years ago
-3x + 4y = -6
Olegator [25]

<em> There is no any c values that would produce a system with no solution because the only c value that makes the line 2 to have the same slope as line 1 also produces the same y-intercept.</em>

<h2>Explanation:</h2>

<h3>Part A.</h3>

A system that has an infinite number of solutions is called Consistent and dependent. If we have a system of linear equations in two variables, then this system will have an infinite number of solutions if and only if the two equations are basically the same. In this case, we have the following system:

\left \{ {{-3x + 4y = -6} \atop {cx + 8y = -12}} \right.

Notice that if we divide the coefficient of the variable y we get:

\frac{8}{4}=2

And if we divide the constant terms we get:

\frac{-12}{-6}=2

So, in order to get c we have:

\frac{c}{-3}=2 \\ \\ \\ Isolating \ c: \\ \\ c=-3(2) \\ \\ c=-6

<h3>Part b.</h3>

A system with no solution is called inconsistent in whose case the two equations will have the same slope but different y-intercepts.

For the first equation we have:

-3x + 4y = -6

But, isolating y, we can write this in slope intercept form :

y=-\frac{3}{4}x-\frac{3}{2}

For the second equation we have:

cx + 8y = -12

But, isolating y, we can write this in slope intercept form :

y=-\frac{c}{8}x-\frac{3}{2}

So the only possible for the line to have the same slope as 1 is that:

-\frac{c}{8}=-\frac{3}{4} \\ \\ c=8(\frac{3}{4}) \\ \\ c=6

So they have the same slope but they also have the same y-intercept making the lines to be the same.

In conclusion,<em> there is no any c values that would produce a system with no solution because the only c value that makes the line 2 to have the same slope as line 1 also produces the same y-intercept.</em>

<h2>Learn more:</h2>

Solving system of linear equations:

brainly.com/question/13799715

#LearnWithBrainly

8 0
3 years ago
Does the number 404,500 have 6 significant figures?
Anestetic [448]

Answer:

It has 4 significant figures, not 6

Step-by-step explanation:

4045 are the significant figures here

6 0
3 years ago
Read 2 more answers
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