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zmey [24]
3 years ago
12

Please help ME I BEG YOU​

Mathematics
2 answers:
kobusy [5.1K]3 years ago
8 0

Answer:

it is also 112°.

Step-by-step explanation:

mark me brainlist amswer.

Nesterboy [21]3 years ago
8 0

Answer:

112°

Step-by-step explanation:

1. The angle with 112 degrees and angle x are corresponding angles, which mean they have the same relative position. Corresponding angles are congruent.

2. Given the information above, m∠x = 112°.

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Answer:

the answer a is false b is true

3 0
3 years ago
If f(x) = -5x – 4 and g(x) = -3x - 2, find (f+ g)(x).
Andrej [43]

Answer: See below

Step-by-step explanation:

(f+g)(x) is another way for saying f(x)+g(x). Since we know f(x) and g(x), we can add them together.

-5x-4+(-3x-2)                  [distribute the 1 to (-3x-2)]

-5x-4-3x-2                      [combine like terms]

-8x-6

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1. Factoring

-2(4x+3)

4 0
3 years ago
Rewrite with only sin x and cos x.
Annette [7]

Option A

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

cos 3x = cos(x + 2x)

We know that,

\cos (a+b)=\cos a \cos b-\sin a \sin b

Therefore,

\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x  ---- eqn 1

We know that,

\sin 2 x=2 \sin x \cos x

\cos 2 x=\cos ^{2} x-\sin ^{2} x

Substituting these values in eqn 1

\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)  -------- eqn 2

We know that,

\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x

Applying this in above eqn 2, we get

\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)

\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}

\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x

Therefore,

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

Option A is correct

7 0
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