Please help me I really need it

3 more than a number then divided the result by 8

ziro4ka [17]

We are given statement : 3 more than a number then divided the result by 8.

We need to write an algebraic expression for it.

Let us assume unknown number be n.

3 more than n = (n+3).

Now, we need to divide that result (n+3) by 8.

So, we would get (n+3) divided by 8 = $\frac{n+3}{8}$ .

<h3>Therefore, final expression is $\frac{n+3}{8}.$ </h3>

5 0

3 years ago

Read 2 more answers

write about which method you prefer to use to divide by 5 counting up, counting back on a number line, or dividing by 10, and th

maria [59]

Answer:

In First method : counting up, counting back on a number line,

If we want the quotient after dividing the number by 5 then we count how many 5 we get from 0 to the dividend.

For example : $\frac{30}{5}$

Since, from 0 to 30 there are six 5's obtained. ( because 5 × 6 = 30 )

Thus, $\frac{30}{5}=6$

In Second Method : dividing by 10, and then doubling the quotient.

First we divide the number by 10 then multiply the quotient by 2.

For Example: $\frac{30}{5}$

Since, $\frac{30}{10}=3$

$2\times 3 = 6$

Thus, $\frac{30}{5}=6$

Now, when we compare the above methods then we conclude that for the smaller numbers first method is appropriate because for small numbers we can easily count total 5's from 0. While for large numbers Second method is appropriate because it is hard to count the total 5's for the large number.

4 0

3 years ago

Read 2 more answers

to exercises 4.141 and 4.137. suppose that y is uniformly distributed on the interval (0, 1) and that a > 0 is a constant. a

Elis [28]

The moment-generating function for y is given as eⁿᵇ - eⁿᵃ / n(b-a) and derivation of moment-generating function of y is e-1/t

Given that,

The interval (0, 1) is covered by a uniform distribution of y, and a > 0 is a constant.

The moment generating function is eⁿᵇ - eⁿᵃ / n(b-a)

The given interval is (0,1)

Here a =0;

b=1;

Now substitute the values of a and b in the above moment generating function we get,

y=eⁿᵇ - eⁿᵃ / n(b-a)

y=e^1-e^0/t(1-0)

y= e-1/t

Therefore, the derivation of the moment generating function is e-1/t

Learn more about moment-generating function here:

brainly.com/question/15061360

#SPJ4

6 0

1 year ago

Verify identity list steps. Cot(t)(1-cos^2(t))=cos(t)sin(t)

storchak [24]

Remember: We have to work from either the LHS or the RHS.
(Left hand side or the Right hand side)

You should already know this:

$\huge{Cot(t) = \frac{1}{tan(t)} = \frac{1}{\frac{sin(t)}{cos(t)}} = 1\div \frac{sin(t)}{cos(t)} = 1\times \frac{cos(t)}{sin(t)}=\boxed{\frac{cos(t)}{sin(t)}}$

You should also know this:

$sin^2(t) + cos^2(t) = 1\\\\\boxed{sin^2(t)} = 1 - cos^2(t)$

So plugging in both of those into our identity, we get:

$\frac{cos(t)}{sin(t)}\cdot sin^2(t) = cos(t)\cdot sin(t)$

Simplify the denominator on the LHS (Left Hand Side)

We get:

$cos(t) \cdot sin(t) = cos(t) \cdot sin(t)$

LHS = RHS

Therefore, identity is verified.

4 0

3 years ago

There is a spinner with 13 equal areas, numbered 1 through 13. If the spinner is spun one time, what is the probability that the

irina [24]

Answer:

0.06

Step-by-step explanation:

probability of multiple of 6= 0.2

probability of multiple of 4= 0.3

0.2 * 0.3 = 0.06

7 0

3 years ago