Since the area of the poster doesn't change by putting it in a frame, we presume the question is asking what the area of the framed poster is.
The length of the poster in its frame is ...
(frame width on one side) + (poster length) + (frame width on the other side)
2 in + 32 in + 2 in = 36 in
Likewise, the width of the poster in its frame is ...
2 in + 24 in + 2 in = 28 in
The area of a rectangle 36 in by 28 in is the product of these dimensions:
Area = (36 in)×(28 in) = (36×28) in² = 1008 in²
Answer:
x = 8.0
Step-by-step explanation:
sin theta = opposite/ hypotenuse
sin 53 = x/10
Multiply by 10 on each side
10 sin 53= x
7.9863551 =x
Rounding to the nearest tenth
8.0 =x
Answer:
least to greatest in order: -5/2(-2.5), -2.5, -2, -1.75, -1, 1.75, 9/4(2.25)
Answer:
your answer would be D....
