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4 years ago

A Mallard duck flies 5/6 of a mile in 1/60 of a hour. Compute the unit rate by setting up a complex fraction and simplifying.

Mathematics

1 answer:

allsm [11]4 years ago

8 0

50 miles per hour hpe it helps

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Is the given function phi(x) = x^2 - x^-1 an explicit solution to the linear equation d^2y/dx^2 - 2/x^2 y = 0? Circle your answe

mart [117]

Answer:

Yes

Step-by-step explanation:

We are given that a function $\phi(x)=x^2-x^{-1}$

We have to find that given function is an explicit solution to the linear equation

$\frac{d^2y}{dx^2}-\frac{2}{x^2}y=0$

If given function is an explicit solution of given linear equation then it satisfied the given differential equation

Differentiate w.r.t x

Then we get $\phi'(x)=2x+x^{-2}$

Again differentiate w.r.t x

Then we get

$\phi''(x)=2-\frac{2}{x^3}$

Substitute all values in the given differential equation

$2-\frac{2}{x^3}-\frac{2}{x^2}(x^2-x^{-1})$

= $2-\frac{2}{x^3}-2+\frac{2}{x^3}=0$

Hence, given function is an explicit solution of given differential equation.

Therefore, answer is yes.

3 0

3 years ago

Please help 20 points ---> Which statement about the Great Compromise is accurate?

Mars2501 [29]

Answer: B. It was a completely new and different plan.

Step-by-step explanation:

5 0

3 years ago

A tank initially contains 50 liters of water with 15kg of salt mixed in. Salt water with concentration 1/3 kg/L runs in at the r

Nimfa-mama [501]

Answer:

13.57 kg

Step-by-step explanation:

Let the amount of salt in a tank be = $\frac{salt in the tank}{volume of salt in the tank}$

= $\frac{15}{50}$

= 0.3 kg/L

The concentration of salt coming into the tank = 0.333kg/L

We know that the concentration of salt leaving the tank should be:

amount of salt in the tank/volume of tank = y(t)/50 L

rate of change of salt = rate in - rate out

$\frac{dy}{dt}$ = 0.66 - $\frac{y}{50}$

solving the differential equation gives :

ln y = 0.66/y (t) - 0.02 t + C

Initial conditions, t= 0; y (0) = 15

then ln 15 = C

ln y = $\frac{0.66}{y}$ t - 0.02t + ln 15

ln $\frac{y}{15}$ = 0.02t

y = 15e( exp -0.02t)

the amount of salt in 5 mins will be:

y (t) = 15e(exp -0.02 (5)

= 13.57 kg

4 0

3 years ago

Write 5/4 as sum of unit fraction

3241004551 [841]

1 and one fourths( 1 1/4)

5 0

3 years ago

Read 2 more answers

Anyone know this? Thanks!

Elan Coil [88]

Answer:

I'm sorry I learned this and I believe yes but I forget

3 0

4 years ago