88.2 is your answer, have a nice day
Answer: by using Poisson distribution
The warranty for a particular system on a new car is 2 years
P(x=2)= 0.143
There is no limit to the number of warranty claims per car
P(X=0) = 0.449
Step-by-step explanation:
<u>step:-1</u>
A random variable X is said to follow a Poisson distribution if it assumes only non-negative values and its probability distribution is given by
P(X=x) = 
here w>0 is called the parameter of the distribution
<u>Step 2</u>:- Given mean value of Poisson distribution = 0.8
The warranty for a particular system a new car is 2 years
P(X=x)=P(X=2)=
P(x=2)= 0.143
<u>Step 3</u>:-
Given mean value of Poisson distribution = 0.8
There is no limit to the number of warranty claims per car
P(X=x)=P(X=0)=
P(X=0) = 0.449
<span>The probability she failed the interview is: 1 - probability she passed the interview.
P( failed 1st interview) = 1 - 0.9 = 0.1
P(failed 2nd interview) = 1 - 0.8 = 0.2.
P(failed 3rd interview) = 1 - 0.7 = 0.3
So we have that if she didn't get the job, the probability that she failed the second interview is 0.2</span>