The solution set of the equation is all reals ⇒ 3rd answer
Step-by-step explanation:
The solution set of an function is the set of all vales make the equation true. The equation has:
- Solution if the left hand side is equal to the right hand side
- No solution if the left hand side doesn't equal the right hand side
∵ The equation is 18 - 3n + 2 = n + 20 - 4n
- Add the like terms in each side
∴ (18 + 2) - 3n = (n - 4n) + 20
∴ 20 - 3n = -3n + 20
- Add 3n to both sides
∴ 20 = 20
In the equation of one variable, when we solve it if the variable is disappeared from the two sides, and the two sides of the equations are equal, then the variable can be any real numbers, if the two sides are not equal, then the variable couldn't be any value
∵ The the variable n is disappeared
∵ The left hand side = the right hand side
∴ n can be any real number
∴ The solution set of the equation is all real numbers
The solution set of the equation is all reals
Learn more:
You can learn more about the equations in brainly.com/question/11229113
#Learnwithbrainly
Your number is 34,699 right and if anything is 5000 or over round ahead so it is 30,000
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.
h'(t) = -32t + 16
When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.
-32t + 16 = 0
-32t = -16
t = 0.5 seconds
b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.
h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet
If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.
c.) We know that the horse is in the air whenever h(t) is greater than 0.
-16t^2 + 16t = 0
-16t(t-1)=0
t = 0 and 1
So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
Answer:
log3 (500)
Step-by-step explanation:
3 log3 (5) * log3(4)
We know that a log b(c) = log b(c^a)
log3 (5)^3 * log3(4)
We know that log a(b) * log a (c) = loga( b*c)
log3 ((5)^3 * 4)
log3 (125*4)
log3 (500)
