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Trava [24]
3 years ago
6

The temperature in London is 4 degrees Celsius on Monday. The temperature in Moscow is -12 degrees Celsius. What is the differen

ce in temperature between the two cities?
Mathematics
1 answer:
VashaNatasha [74]3 years ago
4 0

4 - (-12) = 16

difference = 16 degrees celcius.

<em>request: please mark brainiest, and click the thanks button if correct <3</em>

<em />

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Identify the Asymptotes for the graphs below help pls!
scoray [572]
Asymptotes are lines that continues to approach a given curve but never actually meets it! For the second figure it is the Y axis since the curves slowly appear to approach the Y axis! Not sure about the first figure(probably the X axis)!
5 0
3 years ago
Read 2 more answers
What is the result of subtracting the second equation from the first?<br> -4x-2y=-2<br> x-2y=9
TEA [102]

Answer:

x = 11/5 or 2 1/5

Step-by-step explanation:

propagate the negative through the bottom equation

-5x = -11

x = 11/5

3 0
4 years ago
Given y varies inversely as x, and y = 5 when x = 9. *Write the inverse function
Ivahew [28]

Answer:

y = 45/x

Step-by-step explanation:

Here, we want to write an inverse relationship

for an inverse relationship, the product of both variables will be equal to the constant term

Let us have the constant term as k

Thus, we have it that;

xy = k

9 * 5 = k

k = 45

So the inverse function is;

xy = 45

or y = 45/x

if y is a function of x, we can have it as;

f(x) = 45/x

4 0
3 years ago
There are 3 red balls, 5 green balls, and 1 yellow ball in a hat. If you draw the yellow ball, you gain $10. If you draw any of
shepuryov [24]

Answer:

19.44

Step-by-step explanation:

We have the following information:

3 red balls, 5 green balls, and 1 yellow ball

In total there are 3 + 5 + 1 = 9 balls.

We calculate the probability of each:

Network: 3/9

Green: 5/9

Yellow: 1/9

Each one corresponds a price in profit or losses:

Network: 4

Green: -3

Yellow: 10

So in total it would be the sum of the multiplication of the probability and the price and then multiply everything by 25:

(4 * 3/9 + -3 * 5/9 + 10 * 1/9) * 25 = (0.777) * 25

= 19.44

6 0
3 years ago
The alternating current (AC) breakdown voltage of an insulating liquid indicates its dielectric strength. The article "Testing P
zysi [14]

Answer:

Step-by-step explanation:

Hello!

Given the variable

X: breakdown voltage of an insulating liquid under certain conditions.

a)

Graphic in attachment.

Box: The median is closer to the third quartile than the first quartile showing skewness to the left.

The black dot in the middle of the box represents the sample mean (X[bar]) as you can see it is also moved to the right side of the distribution, affected by the presence of an outlier.

Whiskers:

The upper whisker is smaller than the lower one and there is a value that can be considered an outlier.

Altogether you can say that the distribution of the data set is skewed to the left.

b)

To estimate the population mean you need the population to be at least normal. The box plot shows that the distribution is not symmetrical but, considering that the sample size is n= 48 you can apply the Central Limit Theorem and approximate the sampling distribution to normal.

X[bar]≈N(μ;σ²)

As the distribution is approximate, using the sample standard deviation (since we don't know the population value) for the distribution standard deviation is also valid ⇒ Z= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } }

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

∑X= 2626 ∑X²= 144950 n= 48

X[bar]= ∑X/n= 2626/48= 54.71

S²= 1/n[∑X²- (∑X)²/n]= 1/47[144950-(2626)²/48]= 27.36

S= 5.23

Z_{1-\alpha /2}= Z_{0.975}= 1.96

54.71 ± 1.96 * \frac{5.23}{\sqrt{48} }

[53.22; 56.18]kV

c)

95% CI

amplitude a=2 kV  i.e. semi amplitude d= 1 kV

The semi amplitude or margin of error for the CI can be calculated as:

d= Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

From this formula you can clear the sample size

\frac{d}{Z_{1-\alpha /2}} = \frac{S}{\sqrt{n} }

(\frac{d}{Z_{1-\alpha /2}} )*\sqrt{n} = S

\sqrt{n} = S* (\frac{Z_{1-\alpha /2}}{d} )

n = (S* (\frac{Z_{1-\alpha /2}}{d} ))^2

n= (5.23*(\frac{1.96}{1} ))^2= 105.08= 106

3 0
3 years ago
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