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2 years ago

the perimeter of a rectangular field is 374 yards. if the width of the field is 88 yards, what is its length

Mathematics

1 answer:

aksik [14]2 years ago

3 0

Answer:

99 yards

Step-by-step explanation:

374 - 88 = 286

286 - 88 = 198

198/2 = 99

length = 99

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

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The cost our summer school trip is $17 per students plus a $175 fee for the bus. 1) Write a linear equation for the total cost o

scZoUnD [109]

Answer:

Step-by-step explanation:

1) 17x + 175 = y

2) 17(28) + 175 = y

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3 years ago

Find the perimeter of the triangle defined by the coordinates (7, 1), (-6, 1), and (10, 6). (Round to nearest tenth)

matrenka [14]

Answer:

$35.6\ units$

Step-by-step explanation:

we know that

The perimeter of triangle is equal to the sum of the length of the three sides

Let

$A(7, 1), B(-6, 1), C(10, 6)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(7, 1), B(-6, 1)$

substitute in the formula

$d=\sqrt{(1-1)^{2}+(-6-7)^{2}}$

$d=\sqrt{(0)^{2}+(-13)^{2}}$

$dAB=13\ units$

Find the distance BC

$B(-6, 1), C(10, 6)$

substitute in the formula

$d=\sqrt{(6-1)^{2}+(10+6)^{2}}$

$d=\sqrt{(5)^{2}+(16)^{2}}$

$dBC=16.8\ units$

Find the distance AC

$A(7, 1), C(10, 6)$

substitute in the formula

$d=\sqrt{(6-1)^{2}+(10-7)^{2}}$

$d=\sqrt{(5)^{2}+(3)^{2}}$

$dAC=5.8\ units$

Find the perimeter

$P=dAB+dBC+dAC$

$P=13+16.8+5.8=35.6\ units$

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2 years ago