Answer:
System of two linear equations can't have exactly two solutions. Reason is that when we have two straight lines,they can only intersect at one point of intersection,no more. Or let's see if lines are equivalent,then they have infinitely many solutions,because any point on line can be solution for the system.
Step-by-step explanation:
Answer:
8% tax rate.
Step-by-step explanation:

The 8% (0.08) is the tax rate because the 100%, or 1.00, is the original price of the racket, which was $13.
Answer:
A standard deck of cards consists of 52 cards. The colors are usually black for the spades and clubs and red for the hearts and diamonds.
Step-by-step explanation:
<h3>
Answer: A) Dashed line, shaded below</h3>
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Explanation:
2x + 4y < 16 solves to y < -0.5x+4 when you isolate y. The inequality sign does not change direction because we divided both sides by a positive value (in this case, 4).
The graph of y < -0.5x+4 will be the same as the graph of 2x+4y < 16
To graph y < -0.5x+4, we graph y = -0.5x+4 which is a straight line that goes through the two points (0,4) and (2, 3). This is the boundary line of the inequality shaded region. The boundary line is a dashed line because we are not including points on the boundary that are part of the solution set. We only include these boundary points if the inequality sign has "or equal to".
We then shade below the dashed boundary line to indicate points below the boundary line. The shading is done downward due to the "less than" sign.
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Perhaps another method to find what direction we shade is we can try out a point like (0,0). The point cannot be on the boundary line.
Plug those coordinates into either equation. I'll pick the second equation
y < -0.5x+4
0 < -0.5*0+4
0 < 0+4
0 < 4
The last inequality is true, so the first inequality is also true when (x,y) = (0,0). Therefore, the point (0,0) is in the shaded region. The point (0,0) is below the boundary line y = -0.5x+4
So this is another way to see that the shaded region is below the boundary line.
To find it directly
A = 2 pi r h
A is proportional to rh
factor 2
A is multiplied by 2 * 2 = 4
factor 3
3 * 3 =9
factor 5
5 * 5 = 25
factor 10
10 * 10 = 100
(b) the increase in A by factor x is x^2
c(20)^2 = 400