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Lena [83]
3 years ago
7

According to Okun's law, if the unemployment rate goes from 5% to 3%, what will be the effect on the GDP?

Mathematics
1 answer:
olga2289 [7]3 years ago
5 0

Answer:

D. It will increase by 1%.

Step-by-step explanation:

Given

u_1 = 5\% --- initial rate

u_2 = 3\% --- final rate

Required

The effect on the GDP

To calculate this, we make use of:

\frac{\triangle Y}{Y} = u_1 - 2\triangle u

This gives:

\frac{\triangle Y}{Y} = 5\% - 2(5\% - 3\%)

\frac{\triangle Y}{Y} = 5\% - 2(2\%)

\frac{\triangle Y}{Y} = 5\% - 4\%

\frac{\triangle Y}{Y} = 1\%

<em>This implies that the GDP will increase by 1%</em>

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The length of the third smallest table is 1.6 because 7.8 is more than 3.5 and 3.5 is more than 1.6,

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3 years ago
Need help asap thank you
Angelina_Jolie [31]

Answer:

D is 107 and E is 38

Step-by-step explanation:

20x+40=180

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x=7

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3 years ago
1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.
xxTIMURxx [149]

First, rewrite the equation so that <em>y</em> is a function of <em>x</em> :

x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}

(If you were to plot the actual curve, you would have both y=x^{2/3} and y=-x^{2/3}, but one curve is a reflection of the other, so the arc length for 1 ≤ <em>x</em> ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx

We have

y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}

Then in the integral,

\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx

Substitute

u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx

This transforms the integral to

\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du

and computing it is trivial:

\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)

We can simplify this further to

\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}

7 0
2 years ago
ASAP , I need helppppppp
earnstyle [38]
Answer
D
(20 characters)
8 0
2 years ago
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Evaluate, 2 x {[5 x (60-14 divided by 7)] + 25} x 5=?
Maru [420]
2 * \left \{ [5 * (60-\frac{14 }{7} )] + 25 \right \} * 5=2 * \left \{ [5 * (60-2)] + 25 \right \} * 5= 2 * \left \{ (5 * 58) + 25 \right \} * 5=\\\\= 2 * \left \{ 290 + 25 \right \} * 5=2*315*5=3150


8 0
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