Answer:
<h2>3.6°</h2>
Step-by-step explanation:
The question is incomplete. Here is the complete question.
Find the angle between the given vectors to the nearest tenth of a degree.
u = <8, 7>, v = <9, 7>
we will be using the formula below to calculate the angle between the two vectors;

is the angle between the two vectors.
u = 8i + 7j and v = 9i+7j
u*v = (8i + 7j )*(9i + 7j )
u*v = 8(9) + 7(7)
u*v = 72+49
u*v = 121
|u| = √8²+7²
|u| = √64+49
|u| = √113
|v| = √9²+7²
|v| = √81+49
|v| = √130
Substituting the values into the formula;
121= √113*√130 cos θ
cos θ = 121/121.20
cos θ = 0.998
θ = cos⁻¹0.998
θ = 3.6° (to nearest tenth)
Hence, the angle between the given vectors is 3.6°
I hope this helps you
Area=25x15
Area=375
Answer:
Step-by-step explanation:
Rachel worked for 3 2/3 hours.
Multiply the fractions to get the answer.
2 3/4 x 1 1 /3 is 3 2/3.
Hope it helps you :D
Answer:
X = 4, 1
Step-by-step explanation:
Multiplying out
X^2 - 2x - 3x +6 = 2
X^2 - 5x +4 = 0
Factoring:
X^2 - 4x - X +4
X(x-4) - 1(x-4)
(x-1)(x-4)=0
X= 1, 4
Answer:
x y Negativo tres cuartos Negativo
Step-by-step explanation: