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melamori03 [73]
3 years ago
15

How do I solve for c​

Mathematics
2 answers:
Alex787 [66]3 years ago
6 0
Do the formula c^2=a^2+b^2
Plug in the number
c^2=12^2+5^2
c^2=144+25
c^2=169
Then square root it
Which would get you 13 so
C=13
Hope it helped
MrMuchimi3 years ago
4 0

Answer:

c = 13

Step-by-step explanation:

pythogoras theorem

a² + b² = c²

5² = 25

12² = 144

25 + 144<em> </em>= 169

√169 = 13

c = 13

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What is the area of triangle ABC if a = 7, c = 11, and B = 100°?
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2 years ago
What is the remainder when the polynomial 5x2+10x−15 is divided by x + 5? Enter your answer in the box.
otez555 [7]
ANSWER
The remainder is
60

EXPLANATION

Let

p(x) = 5 {x}^{2}  + 10x - 15

We shall apply the remainder theorem to obtain the remainder when
p(x)
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x + 5

According to the remainder theorem, if a polynomial
p(x)
is divided by
x - a
then the remainder is
p(a)


So we set
x + 5 = 0

and solve for
x

to obtain,

x =  - 5


We now substitute -5 into the given polynomial to find the remainder.



p( - 5) = 5 {( - 5)}^{2}  + 10( - 5) - 15


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p( - 5) = 5(25) - 50 - 15

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3 years ago
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Michael has a substantial student debt, but he recently got a new job, which came with a signing bonus. He calculates that with
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3 years ago
Nine cars (3 Pontiacs [labeled 1-3], 4 Fords [labeled 4-7], and 2 Chevrolet's [labeled 8-9]) are divided into 3 groups for car r
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Answer:

The number of different ways to arrange the 9 cars is 362,880.

Step-by-step explanation:

There are a total of 9 cars.

These 9 cars are to divided among 3 racing groups.

The condition applied is that there should be 3 cars in each group.

Use permutation to determine the total number of arrangements of the cars.

  • For group 1:

       There are 9 cars and 3 to be allotted to group 1.

       This can happen in ^9P_{3} ways.

        That is, ^9P_{3}=\frac{9!}{(9-3)!} =504 ways.

  • For group 2:

       There are remaining 6 cars and 3 to be allotted to group 2.

       This can happen in ^6P_{3} ways.

        That is, ^6P_{3}=\frac{6!}{(6-3)!} =120 ways.

  • For group 3:

       There are remaining 3 cars and 3 to be allotted to group 3.

       This can happen in ^3P_{3} ways.

        That is, ^3P_{3}=\frac{3!}{(3-3)!} =6 ways.

The total number of ways to arrange the 9 cars is: ^9P_{3}\times ^6P_{3}\times ^3P_{3}=504\times120\times6=362880

Thus, the number of different ways to arrange the 9 cars is 362,880.

7 0
4 years ago
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