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Murljashka [212]
3 years ago
7

Nine cars (3 Pontiacs [labeled 1-3], 4 Fords [labeled 4-7], and 2 Chevrolet's [labeled 8-9]) are divided into 3 groups for car r

acing. each group consistes of 3 cars, and they are allocated to 3 tracks (1-3), respectively.
1. How many different ways can you arrange the 9 cars?
Mathematics
1 answer:
STatiana [176]3 years ago
7 0

Answer:

The number of different ways to arrange the 9 cars is 362,880.

Step-by-step explanation:

There are a total of 9 cars.

These 9 cars are to divided among 3 racing groups.

The condition applied is that there should be 3 cars in each group.

Use permutation to determine the total number of arrangements of the cars.

  • For group 1:

       There are 9 cars and 3 to be allotted to group 1.

       This can happen in ^9P_{3} ways.

        That is, ^9P_{3}=\frac{9!}{(9-3)!} =504 ways.

  • For group 2:

       There are remaining 6 cars and 3 to be allotted to group 2.

       This can happen in ^6P_{3} ways.

        That is, ^6P_{3}=\frac{6!}{(6-3)!} =120 ways.

  • For group 3:

       There are remaining 3 cars and 3 to be allotted to group 3.

       This can happen in ^3P_{3} ways.

        That is, ^3P_{3}=\frac{3!}{(3-3)!} =6 ways.

The total number of ways to arrange the 9 cars is: ^9P_{3}\times ^6P_{3}\times ^3P_{3}=504\times120\times6=362880

Thus, the number of different ways to arrange the 9 cars is 362,880.

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============================================================

Problem 19

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-------------------------------

Explanation:

The horizontal lines are parallel. Note the arrow markers along the interior portion of the lines. These similar markers tell us how the lines pair up to be parallel to one another.

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============================================================

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