Question

Which equation is the slope-intercept form of the line that passes through (6, –11) and is parallel to the graph of y = –2/3x + 12?
A. y = –2/3x – 7
B. y = –2/3x – 6
C. y = 2/3x – 5
D. y = 2/3x – 15

Answer 1

Answer:

The answer is option A

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the parallel line we must first find the slope of the original line

From the question the original line is

y = - ⅔x + 12

Comparing with the general equation above

Slope = -⅔

Since the lines are parallel their slope are also the same

Slope of parallel line = - ⅔

The equation of the line using point

(6, –11) and slope - ⅔ is

$y + 11 = - \frac{2}{3} (x - 6) \\ y + 11 = - \frac{2}{3} x + 4 \\ y = - \frac{2}{3} x + 4 - 11$

We have the final answer as

$y = - \frac{2}{ 3 } x - 7$

Hope this helps you