Which equation is the slope-intercept form of the line that passes through (6, –11) and is parallel to the graph of y = –2/3x +
1 answer:
Answer:
<h2>The answer is option A</h2>Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
To find the equation of the parallel line we must first find the slope of the original line
From the question the original line is
y = - ⅔x + 12
Comparing with the general equation above
Slope = -⅔
Since the lines are parallel their slope are also the same
Slope of parallel line = - ⅔
The equation of the line using point
(6, –11) and slope - ⅔ is
We have the final answer as
Hope this helps you
You might be interested in
Answer:
Answer C --> y = 1/3 sin(x)
Step-by-step explanation:
When you are finding the inverse of a function, you are trying to obtain the function that applied to the one given gives you as result EXACTLY "x".
You know that the function sin(x) is the inverse of Arcsin(x), because when you applied it as follows, you obtain x (by cancelling out Arcsin and "liberating" the argument inside it: "x") :
But in this case applying sin (x) to Arcsin (3x) will not render just x, because the argument that ARcsin is carrying is not just "x" but "3x":
So we need to divide by 3 as well in order to obtain just "x" after applying our inverse. The function that does such is the third one listed (C), sinc it also has a multiplicative 1/3 that will cancel the factor 3 we want to get rid of.