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Stella [2.4K]
3 years ago
10

On the floor plan shown at the right 1.25 inches represents 2 feet. A. what is the actual length of the entire floor? B. what is

the actual area of the entire floor? explain how you found the area. please answer Part A and B
Mathematics
2 answers:
mel-nik [20]3 years ago
7 0

Answer:

19.2

Step-by-step explanation:

uranmaximum [27]3 years ago
5 0

Answer:

3

Step-by-step explanation:

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There are 81 red, blue and yellow
wel

Step-by-step explanation:

Here Given

Total counters = 81

red counters are 9 more than the yellow ones.

And Yellow counter = blue counter

So let the Yellow counter be x and as blue counter and yellow counter are same then blue counter will be also x

And by the question

Red counter = 9 + x

Now

9 + x + x + x = 81

9 + 3x = 81

3x = 81 - 9

3x = 72

x = 72 / 3

Therefore x = 24

Now

Red counters = 9 + 24 = 33

Blue counters = 24

Yellow counters = 24

Hope it helped :)

3 0
3 years ago
Read 2 more answers
Suppose the number of dropped footballs for a wide receiver, over the course of a season, are normally distributed with a mean o
inessss [21]
The z-score is the number of standard deviations away from the mean. We first subtract the actual score from the mean, then divide the difference by the standard deviation. In this case, our actual score is 13, so we subtract from the mean of 16, then divide by the SD of 2
(13 - 16) / 2 = -1.5
8 0
3 years ago
What is the solution to this equation? 2 x + 3 = x − 4
Mrrafil [7]

Answer:

the answer is -7

Step-by-step explanation:

hope this helps

4 0
4 years ago
Read 2 more answers
A box contains eighteen $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill. You blindly reach into the
zubka84 [21]

Answer:  $7.70

Step-by-step explanation:

Given : A box contains eighteen $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill.

Total bills = 18+10+8+3+1=40

We know that probability of any event =\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

i.e. the probability of getting $1 bills =P(E_1)=\dfrac{18}{40}=0.45

Probability of getting $10 bills =P(E_2)=\dfrac{10}{40}=0.25

Probability of getting $5 bills =P(E_3)=\dfrac{8}{40}=0.2

Probability of getting $20 bills =P(E_4)=\dfrac{3}{40}=0.075

Probability of getting $100 bills =P(E_5)=\dfrac{1}{40}=0.025

\text{Expected value =}1\times P(E_1)+5\times P(E_2)+10\times P(E_3)+20\times P(E_4)+100\times P(E_5)\\\\=1\times 0.45+5\times 0.25+10\times0.2+20\times 0.075+100\times 0.025\\\\=7.7

Hence, the expected value of your draw= $7.70

5 0
4 years ago
The final exam scores in a statistics class were normally distributed with a mean of 70 and a standard deviation of five. What i
sp2606 [1]

The probability that a student scored less than 55% on the exam is 0.134%.

<h3>What is a normal distribution?</h3>

It's the probability curve of a continuous distribution that's most likely symmetric around the mean. On the Z curve, at Z=0, the chance is 50-50. A bell-shaped curve is another name for it.

We have:

Mean of the sample = 70

Standard deviation = 5

= P(X<55%)

Z = (55-70)/5

Z = -3

P(X < -3)

From the Z table:

P(x<-3) = 0.0013499

or

P(x<-3) = 0.134%  

Thus, the probability that a student scored less than 55% on the exam is 0.134%.

Learn more about the normal distribution here:

brainly.com/question/12421652

#SPJ1

8 0
2 years ago
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