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3 years ago

What is the length of AB?

Mathematics

1 answer:

DENIUS [597]3 years ago

7 0

Answer:

C=10

Step-by-step explanation:

A^2 + B^2 = C^2

A=6

B=8

C=?

A^2=36

B^2=64

C^2=100

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5|2x - 3| + 4 = 9 How do you solve this

agasfer [191]

Answer:

x = 2, or x = -1

Step-by-step explanation:

If 2x - 3 is inside the parenthesis (), then the value of x is 2.

If 2x - 3 is inside the absolute value sign, then the value of x will probably be -1.

Solution 1

(10x-15) + 4 = 9

10x -11 = 9

10x = 20 -> x = 2

Solution 2 (Not 100% sure)

|10x -15| +4 = 9

10x + 15 +4 = 9

10x + 19 = 9

10x = -10 -> x = -1

Please correct me if I'm wrong.

3 0

3 years ago

When is it helpful to estimate quotients?

pantera1 [17]

It is helpful to estimate quotients when the number is very big.

3 0

3 years ago

Please help, I need input on if I did this correctly and you just substitute.

kow [346]

The value of h(t) when $t=\frac{15}{32}$ is 10.02.

Solution:

Given function $h(t)=-16t^2+15t+6.5$

To find the value of h(t) when $t=\frac{15}{32}$ :

$h(t)=-16t^2+15t+6.5$

Substitute $t=\frac{15}{32}$ in the given function.

$$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5$

$$=-16\left(\frac{225}{1024} \right)+15\left(\frac{15}{32} \right)+6.5$

Now multiply the common terms into inside the bracket.

$$=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5$

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

$$=-\left(\frac{225}{64} \right)+\left(\frac{225}{32} \right)+6.5$

To make the denominator same, take LCM of the denominators.

LCM of 64 and 32 = 64

$$=-\left(\frac{225}{64} \right)+\left(\frac{225\times2}{32\times2} \right)+6.5\times\frac{64}{64}$

$$=-\frac{225}{64} +\frac{450}{64}+\frac{416}{64}$

$$=\frac{-225+450+416}{64}$

$$=\frac{641}{64}$

= 10.02

$$h\left(\frac{15}{32} \right)=10.02$

Hence the value of h(t) when $t=\frac{15}{32}$ is 10.02.

8 0

3 years ago

Smooth, suave, ingratiatingly pleasant

mash [69]

I say the answer is B. Bland

4 0

3 years ago

HELPPPPP

SSSSS [86.1K]

Hello there,

From Point A to Point B Peter traveled roughly 30 miles in 30 minutes.

From Point B to Point C Peter traveled roughly 130 miles in 2 hours and 30 minutes.

From Point C he didn't move in distance but the hours moved so c is out.

From Point C to Point D, Peter traveled roughly 180 miles in 3 hours.

Therefore D Peter had the fastest interval at D.

8 0

3 years ago