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2 years ago

If 1/4x +2y= 11/4 and - 6y - x = 7, what is half of y?

Mathematics

1 answer:

ioda2 years ago

8 0

Answer:

y/2 = 4.5

Step-by-step explanation:

1/4x + 2y = 11/4

distribute by 4 to eliminate fractions

x + 8y = 11

+ <u>-x - 6y = 7</u>

2y = 18

y = 9

half of 9 = 4 1/2

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3 years ago

1. Which inference can you make by comparing the measures of center?

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Answer:

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2 years ago

Write the limit as a definite integral on the interval [a, b], where ci is any point in the ith subinterval. Limit Interval lim

geniusboy [140]

Answer:

The corresponding definite integral may be written as

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x$

The answer of the above definite integral is

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98$

Step-by-step explanation:

The given limit interval is

$\lim_{||\Delta|| \to 0} \sum\limits_{i=1}^n (4c_i + 11) \Delta x_i$

$[a, b] = [-8, 6]$

The corresponding definite integral may be written as

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x$

$\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x$

Bonus:

The definite integral may be solved as

$\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x \\\\\frac{4x^2}{2} + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\2x^2 + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\ 2(6^2 -(-8)^2 ) + 11(6 - (-8) \\\\2(36 - 64 ) + 11(6 + 8) \\\\2(-28 ) + 11(14) \\\\-56 +154 \\\\98$

Therefore, the answer to the integral is

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98$

5 0

3 years ago

The sum of two-thirds of a number and twenty

Ede4ka [16]

Answer:

2/3n + 20

Step-by-step explanation:

4 0

3 years ago

Given the following functions f(x) and g(x), solve f over g (−5) and select the correct answer below:

ahrayia [7]

Plug -5 into both of them and divide:

$\sf\dfrac{2x-20}{x-1}$

$\sf\dfrac{2(-5)-20}{-5-1}$

Simplify:

$\sf\dfrac{-10-20}{-6}$

$\sf\dfrac{-30}{-6}$

$\boxed{\sf 5}$

7 0

3 years ago

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