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Mark brainliest please
Hope this helps you
If she maintains her average amount of movies bought every week, then she will buy 20 DVDs in 10 weeks. Explanation: she buys 4 every week, so if we want to find out how many are in 10 weeks, we must multiply two until we get to 10 ( five weeks ) then multiply that buy her average of movies. And that is how we get the answer of 20 DVDs! ( her at least I did )
Anyways, hope this helps!
12 girls out of 30 were selected, so the ratio "selected:tried" if 12/30. This fraction can be simplified into

Similarly, 16 boys out of 40 were selected, so the ratio "selected:tried" if 16/40. This fraction can be simplified into

So yes, the ratio of the number of students on the team to the number of students trying out the same for both boys and girls
To find the z-score for a weight of 196 oz., use

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.
Answer:
The answer is B hope this helps